Answer:
D. Graphing the force as a function of distance and calculating the area under the curve.
Explanation:
Answer:
Explanation:
Given that
Charge on ring 1 is q1 and radius is R.
Charge on ring 2 is q2 and radius is R.
Distance ,d= 3 R
So the total electric field at point P is given as follows
Given that distance from ring 1 is R
I have the answer for A. Since there is blockage in the ear canal, some sound waves may not be able to get through or travel as quickly so you would have trouble hearing
Answer:
This is because when the pedal sprocket arms are in the horizontal position, it is perpendicular to the applied force, and the angle between the applied force and the pedal sprocket arms is 90⁰.
Also, when the pedal sprocket arms are in the vertical position, it is parallel to the applied force, and the angle between the applied force and the pedal sprocket arms is 0⁰.
Explanation:
τ = r×F×sinθ
where;
τ is the torque produced
r is the radius of the pedal sprocket arms
F is the applied force
θ is the angle between the applied force and the pedal sprocket arms
Maximum torque depends on the value of θ,
when the pedal sprocket arms are in the horizontal position, it is perpendicular to the applied force, and the angle between the applied force and the pedal sprocket arms is 90⁰.
τ = r×F×sin90⁰ = τ = r×F(1) = Fr (maximum value of torque)
Also, when the pedal sprocket arms are in the vertical position, it is parallel to the applied force, and the angle between the applied force and the pedal sprocket arms is 0⁰.
τ = r×F×sin0⁰ = τ = r×F(0) = 0 (torque is zero).
Answer:
Total load = 2999.126 kg
Explanation:
Let the spring constant of the shock absorber be k.
We know that the force applied on a spring is directly proportional to elongated length and the constant of proportionality is called spring constant.
Thus
Force, F = kx
where,
x = elongation = 9.1 cm 0.091 m
mass of the people, m = 127 kg
F = weight of the people = mg = 127 x 9.8 = 1244.6 N
substituting these values in the first equation,
1244.6 = k x 0.091
thus, k = 13,676.923 N/m
Now we know that the time period, T of an oscillating spring with a load of mass m is
thus,
T = 1.66s
substituting these values in the equation,
m = 2999.126 kg
