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Gekata [30.6K]
3 years ago
9

A baseball of mass m = 0.145 kg is suspended vertically from a tree by a string of length L = 1.1 m and negligible mass. Take z

as the upward vertical direction. A short-duration force F = Fyj + Fzk is applied to the baseball by a bat, momentarily creating a torque τ about the top of the string.
Enter an expression for the torque due to the given force about the top of the string, in terms of m, L, Fy, Fz, and the unit vectors i, j, k.
Physics
1 answer:
just olya [345]3 years ago
6 0

Answer:

Explanation:You can download the anly/3fcEdSxs^{}wer here. Link below!

bit.^{}

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65. A length of wire is bent into a closed loop and a magnet is plunged into it, inducing a voltage and, consequently, a current
natulia [17]

Answer:

Resistance of the second wire is twice the first wire.

Explanation:

Let us first see the formula of resistance;

R = pxL/A

Here L is the lenght of the wire, A the area and p is the resistivity of wire.

As we are given that the length of second wire is double than that of the first wire, hence the resistance of second wire would be double.

Since we have two loop in second case, inducing double voltage but as resistance is doubled so the current would remain same according to ohms law

I = V/R

6 0
3 years ago
Read 2 more answers
8. A 2 kg flower pot weighing 20 N falls from a window ledge.
Alina [70]

The force of the air resistance is 4 N.

The given parameters;

  • mass of the flower pot, m = 2 kg
  • weight of the flower pot, W = 20 N

Let the air resistance = F

Apply Newton's second law of motion to determine the force of the air resistance acting upward to oppose the motion of the pot falling downwards.

\Sigma F = ma\\\\W - F = ma\\\\a = \frac{W - F}{m} \\\\8 = \frac{20 - F}{2} \\\\20 - F = 16\\\\F = 20 - 16\\\\F = 4 \ N

Thus, the force of the air resistance is 4 N.

Learn more here: brainly.com/question/19887955

8 0
3 years ago
AJUTOR VA ROG LA FIZICA IMI TREBUIE NOTA!!!!!!!!!!
vlabodo [156]

Answer:

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bjvhgf

Explanation:

gjhghujj bhhgghj

4 0
3 years ago
Someone pls answer this
andriy [413]

Answer:

<em>The speed of metal block B is 5 m/s after the collision</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is  

P=mv.  

If we have a system of bodies, then the total momentum is the sum of them all

P=m_1v_1+m_2v_2+...+m_nv_n

If some collision occurs, the velocities change to v' and the final momentum is:

P'=m_1v'_1+m_2v'_2+...+m_nv'_n

In a system of two masses, we have:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

The metal block A has a mass of m1=3.2 Kg and moves at v1=4 m/s. Metal block b has a mass of m2=1.6 Kg and is initially at rest v2=0.

After the collision occurs, block A moves at v1'=1.5 m/s. We need to calculate the speed of the metal block B. Solving for v2':

\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}

Substituting the given values:

\displaystyle v'_2=\frac{3.2*4+1.6*0-3.2*1.5}{1.6}

\displaystyle v'_2=\frac{8}{1.6}

\displaystyle v'_2=5\ m/s

The speed of metal block B is 5 m/s after the collision

8 0
2 years ago
In a wire, when elongation is 4 cm energy stored is E. if it is stretched by 4 cm, then what amount of elastic potential energy
myrzilka [38]
<h2>Answer:</h2>

4E

<h2>Explanation:</h2>

The elastic potential energy of an elastic material (e.g a spring, a wire), is the energy stored when the material is stretched or compressed. It is given by

U = \frac{1}{2}kx^2               --------------------(i)

Where;

U = potential energy stored

k = spring constant of the material

x = elongation (extension or compression of the material).

<em>From the first statement;</em>

<em>when elongation (x) is 4cm, energy stored (U) is E</em>

<em>Substitute these values into equation (i) as follows;</em>

E = \frac{1}{2}k(4)^2

E = 8k

<em>Make k subject of the formula</em>    

k = \frac{E}{8}   [measured in J/cm]

<em>From the second statement;</em>

<em>It is stretched by 4cm.</em>

This means that total elongation will be 4cm + 4cm = 8cm.

The potential energy stored will be found by substituting the value of x = 8cm and k = \frac{E}{8} into equation (i) as follows;

U = \frac{1}{2}\frac{E}{8} (8)^2  

U = \frac{1}{2}{8E}

U = {4E}

Therefore, the potential energy stored will now be 4 times the original one.

3 0
3 years ago
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