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3 years ago

14

The Milky Way Galaxy is (a) another name for our solar system; (b) a small group of stars visible in our night sky; (c) a collec

tion of more than 100 billion stars, of which our Sun is one

1 answer:

gtnhenbr [62]3 years ago

3 0

Answer:

C

Explanation:

please give brainliest

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What is the temperature of a sample of gas when the average translational kinetic energy of a molecule in the sample is 8.37 × 1

-BARSIC- [3]

Answer:

404K

Explanation:

Data given, Kinetic Energy.K.E=8.37*10^-21J

Note: as the temperature of a is increase, the rate of random movement will increase, hence leading to more collision per unit time. Hence we can say that the relationship between the kinetic energy and the temperature is a direct variation.

This relationship can be expressed as

$K.E=\frac{3}{2}KT$

where K is a constant of value 1.38*10^-23

Hence if we substitute the values, we arrive at

$T=\frac{2/3(8.37*10^{-21})}{1.38*10^-23}\\ T=404K$

converting to degree we have $131^{0}C$

4 0

3 years ago

What do you think would happen to the boiling point of water if you were to cook pasta near the Dead Sea in Israel, which is 1,2

mina [271]

Answer:

I think it will be the same.

5 0

3 years ago

Read 2 more answers

A rectangular block measures 4.1cm by 2.8cm by 2.1cm. calculate its volume given you answer to an appropriate number of signific

sattari [20]

Answer:

Volume = 24 cm^3

Explanation:

We recall that the volume of the box is calculated via the formula:

Volume = length * height * width

and that in a product, the number of significant figures for the result should coincide with the number of significant figures of the factor that has the least of them.

In this case, all measures have the same number of significant figures: two. so we calculate the product, and then limit the answer value to exactly two significant figures:

Volume = 4.1 cm * 2.8 cm * 2.1 cm = 24.108 cm^3, which must be rounded to two significant figures as: 24 cm^3

6 0

3 years ago

Read 2 more answers

A steel playground slide is 5.25 m long and is raised 2.75 m on one end. A 45.0 kg child slides down from the top starting at re

Temka [501]

Answer:

$F=32.24N$

Explanation:

From the question we are told that:

Height $h= 2.75 m$

Length $l = 5.25 m$

Mass $m=45kg$

Final speed $v_f=6.81$

Generally the equation for Potential Energy P.E is mathematically given by

$P.E=mgh$

Therefore

Initial potential energy

$P.E_1=45*9.8*2.75 \\\\P.E_1= 1212.75 J$

Generally the equation for Kinetic Energy K.E is mathematically given by

$K.E=0.5mv^2$

Therefore

Final kinetic energy

$K.E_2= 1/2*45*6.81*6.81 \\\\K.E_2= 1043.46J$

Generally the equation for Work_done is mathematically given by

$W=P.E_1-K.E_2\\\\W=169.3$

Therefore

$F=\frac{W}{d}\\\\F=\frac{169.3}{5.25}$

$F=32.24N$

8 0

3 years ago

While filming an intense action sequence for the next James Bond movie, a controlled explosion detonates 1.3 km away from the ac

brilliants [131]

To solve this problem we must basically resort to the kinematic equations of movement. For which speed is defined as the distance traveled in a given time. Mathematically this can be expressed as

$v = \frac{d}{t}$

Where

d = Distance

t = time

For which clearing the time we will have the expression

$t = \frac{d}{v}$

Since we have two 'fluids' in which the sound travels at different speeds we will have that for the rock the time elapsed to feel the explosion will be:

$t = \frac{1300m}{3000m/s}$

$t = 0.433s$

In the case of the atmosphere -composite of air- the average speed of sound is 343m / s, therefore it will take

$t = \frac{1300m}{343m/s}$

$t = 3.79s$

The total difference between the two times would be

$\Delta t = 3.79s-0.433s$

$\Delta t = 3.357s$

Therefore 3.357s will pass between when they feel the explosion and when they hear it

8 0

4 years ago