Answer:
Isolation of Variables.
Explanation:
I am just taking a guess but Experimental investigations allow you to isolate variables (making most variables constant, allowing only the independent variable to have an impact on the dependent variable). With other scientific investigations, if they don't isolate the variables it is very possible that an unknown third variable could be skewing the results (which will result in correlation but not causation).
Answer:
784N
Explanation:
Yo need to multiply the mass of the person by th Earth's gravity, which we know is 9.8m/s²
80kg*9.8m/s² = 784N
Answer:
F = 62.4 N
Explanation:
We must solve this problem in two parts, the first with energy to find the speed with which it reaches the grass and with impulse to determine the strength in the grass
Let's look for the speed of arrival to the grass, write the energy in two points
Initial
Em₀ = U = m g h
Point 2, just by touching the grass
Em₂ = K = ½ m v²
Em₀ = Em₂
m g h = ½ m v²
v = √ 2gh
v = √( 2 9.8 2.8)
v = 7.4 m/s
Let's calculate the momentum until it stops
I = F t = m vf -m v₀
I = 0-0.15 (-7.4)
I = 1.11 N s
We must find the time during which the apple stops, let's use kinematics to find the average acceleration
= v = 7.4 m/s
² = v₀² + 2 a y
0 = v₀² + 2 a y
a = v₀² / 2y
a = 7.4²/2 0.066
a = 414.85 m / s²
Now let's look for the time to stop with this acceleration
= v₀ + at
0 = v₀ + at
t = v₀ / a
t = 7.4 / 414.85
t = 0.0178 s
Let's calculate with the momentum
I = F t
F = I / t
F = 1.11 / 0.0178
F = 62.4 N
Answer:
An antimony can form 3 bonds
Let me know if this helps
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Explanation:
Answer:
Part a)
Time to reach the maximum height is given as
B)
Maximum height of the bullet is
C)
Horizontal range of the bullet is
Part d)
Final velocity of the bullet is v = 600 m/s at 30 degree
Explanation:
A) As we know that velocity of the bullet is
v = 600 m/s
So we have
Now time to reach the maximum height is given as
B) As we know that the object have zero final speed in y direction
C)
Now the horizontal displacement of the object in total time of flight is known as range of projectile
So we have
Part d)
As we know that the final height is same as that of initial So it will strike the ground at same velocity as that of initial velocity
So we have
v = 600 m/s at 30 degree