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2 years ago

Magnetic fields go from the north poles of magnets to the south poles of magnets. true or false

Physics

1 answer:

Novay_Z [31]2 years ago

7 0

The Answer is true, the saying opposites attract are true for magnets when poles match though they repel.

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A visible violet light emits light with a wavelength of 4.00 × 10-7 m.

RideAnS [48]

Answer:

The correct option is B. 7.5 * 10¹⁴ Hz

Explanation:

Frequency = (speed) / (wavelength)

= (3 x 10⁸ m/s) / (4 x 10⁻⁷ m)

= (3/4 x 10¹⁵) ( m / m - s )

= (0.75 x 10¹⁵) /sec

= 7.5 x 10¹⁴ Hz

= 750,000 GHz

4 0

2 years ago

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3 simple machines you find in a pinball machine

cestrela7 [59]

lever (The things that flick the ball around)

Inclined plane (The hill the ball rolls down)

Wedge (The bumps that stop the ball from rolling certain places)

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1 year ago

Two energy resources that do not depend on the sun's energy

Stolb23 [73]

Windmill and waterweel

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3 years ago

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In a hot summer day, a spherical air bubble that has a volume of 1.20 cm3 is released at temperature 17.0 °C by a scuba diver 25

anastassius [24]

Answer:

The radius of the bubble when it reaches the surface at 30 ºC is 1.015 centimeters.

Explanation:

Let suppose that air bubble behaves as ideal gas, whose equation of state is:

$P\cdot V = n\cdot R_{u}\cdot T$ (Eq. 1)

Where:

$P$ - Pressure of the bubble, measured in kilopascals.

$V$ - Volume of the bubble, measured in cubic meters.

$n$ - Molar amount of the bubble, measured in kilomoles.

$T$ - Temperature, measured in Kelvin.

$R_{u}$ - Ideal gas constant, measured in kilopascal-cubic meter per kilomole-Kelvin.

Then, we eliminate the molar amount and the ideal gas constant by constructing the following relationship:

$\frac{P_{A}\cdot V_{A}}{T_{A}} = \frac{P_{B}\cdot V_{B}}{T_{B}}$ (Eq. 2)

Where:

$P_{A}$ , $P_{B}$ - Pressure of the bubble at bottom and surface, measured in kilopascals.

$V_{A}$ , $V_{B}$ - Volume of the bubble at bottom and surface, measured in cubic meters.

$T_{A}$ , $T_{B}$ - Temperature of the bubble at bottom and surface, measured in Kelvin.

The pressure experimented by the bubble at bottom and surface are, respectively:

$P_{A} = 101.325\,kPa+\left(1027\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{kg}{m^{3}} \right)\cdot (25\,m)\cdot \left(\frac{1}{1000}\,\frac{kPa}{Pa} \right)$

$P_{A} = 353.120\,kPa$

$P_{B} = 101.325\,kPa$

If we know that $P_{A} = 353.120\,kPa$ , $P_{B} = 101.325\,kPa$ , $V_{A} = 1.20\times 10^{-6}\,m^{3}$ , $T_{A} = 290.15\,K$ and $T_{B} = 303.15\,K$ , then the volume of the bubble at surface is: