1 and 2 please help me!??

If the treadmill’s initial speed is 1.7m/s, what will its final speed be?

GalinKa [24]

For how long? Or is it just speed ??

6 0

3 years ago

A hanging wire made of an alloy of titanium with diameter 0.05 cm is initially 2.7 m long. When a 15 kg mass is hung from it, th

Svet_ta [14]

Answer:

Explanation:

Young's modulus of elasticity Y = stress / strain

stress = force / cross sectional area

= weight of 15 kg / π r²

= 15 x 9.8 / 3.14 x ( .025 x 10⁻² )²

stress = 74.9 x 10⁷ N / m²

strain = Δ L / L , Δ L is change in length and L is original length

Putting the values

strain = .0168 / 2.7 =.006222

Young's modulus of elasticity Y = 74.9 x 10⁷ / .006222

= 120.88 x 10⁹ N / m² .

8 0

3 years ago

An incompressible fluid is flowing through a horizontal pipe with a constriction. The velocity of the fluid in the wide section

lapo4ka [179]

The Bermoulli's equation allows us to find the pressure in the narrow part of the pipe through which water circulates is:

P = 500 Pa

Bernoulli's equation is the work-energy relationship for fluids that are liquids and gases.

$P_1 + \frac{1}{2} \rho v_1^2 + \rho g y_1 = P2 + \frac{1}{2} \rho v_2^2 + \rho g y_2$

Where the subscripts 1 and 2 represent points of interest, P is the pressure, ρ the density of the fluid, v the velocity and y the height.

They indicate that the pipe is horizontal, that the pressure in the wide part P₁ = 200 kPa and the velocity is v₁ = 5 m / s and in the narrow part v₂=8.00 m/s, see attached.

Since the pipe is horizontal y₁ = y₂

P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²

P₂ = P₁ + ½ ρ (v₁² - v₂²)

Let's calculate

P₂ = 200 10² + ½ ρ (5² - 8²)

P₂ = 2 10⁴ - 19.5 ρ

For a specific calculation the value of the density of the fluid is needed, suppose that the fluid is water ρ = 1000 kg / m³

P₂ = 2 10² - 19.5 1000

P₂ = 500 Pa

In conclusion using the Bermoulli equation we can find the pressure in the narrow part of the pipe through which water circulates is:

P = 500 Pa

Learn more here: brainly.com/question/9506577

3 0

3 years ago

An object starts at rest then accelerates at a rate of 5m/s^2 for 1 second and then 2m/s^2 for 2 seconds. What is the average ac

inn [45]

Acceleration = (change in speed) / (time for the change)

-- during the first second, the object increases its speed to

(5 m/s²) · (1 s) = 5 m/s .

-- During the next 2 seconds, the object increases its speed by

(2 m/s²) · ( s) = 4 m/s

So at the end of the whole 3 seconds, its speed is (5 m/s) + (4 m/s) = 9 m/s

-- Over the whole time, its speed has changed from zero to 9 m/s.

Acceleration = (change in speed) / (time for the change)

Acceleration = (9 m/s) / (3 sec)

Acceleration = 3 m/s²

7 0

3 years ago

A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0°. What is the va

zloy xaker [14]

Answer:

The value of work being done on the object is 958J.

Explanation:

Work done is equal to force multiply by distance, but when the angle is between the force and distance work done=Force (cos theta) × distance

Work done = Force(cos theta) × distance

Work done = 25N(cos 40.0°) × 50m

Work done = 25N(0.7660) × 50m

Work done = 19.15N × 50m

Work done = 957.5J = 958J

Therefore the value of work being done on the object is 958J.

3 0

2 years ago