Q2. A certain machine is used to lift a load of 500N when an effort of 50N is applied to the machine the load is raised by 10m a
2 answers:
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Answer : The final temperature of the mixture is
Explanation :
First we have to calculate the mass of water.
Mass = Density × Volume
Density of water = 1.00 g/mL
Mass = 1.00 g/mL × 180 cm³ = 180 g
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of hot water (liquid) =
= specific heat of ice (solid)=
= mass of hot water = 180 g
= mass of ice = 20 g
= final temperature of mixture = ?
= initial temperature of hot water =
= initial temperature of ice =
Now put all the given values in the above formula, we get
Therefore, the final temperature of the mixture is