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Marizza181 [45]
2 years ago
5

Q2. A certain machine is used to lift a load of 500N when an effort of 50N is applied to the machine the load is raised by 10m a

nd effort is moved by 60m that is the efficiency of the machine? (1. sp)​
Physics
2 answers:
Natalija [7]2 years ago
8 0

Answer:

2%

Explanation:

E=l/E x r/R x100%

=5000/50 x 0.1/0.6 x100

=2% or 166.7

White raven [17]2 years ago
6 0
Answer:
166.667%
Explanation:
MA = 500/50
. = 10
VR=60/10
=6
Efficiency=10/6 X 100%
=166.667
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nata0808 [166]
I think it is -3.99 x 102 j
6 0
3 years ago
An electron moving with a velocity = 5.0 × 107 m/s enters a region of space where perpendicular electric and a magnetic fields a
Cloud [144]

Answer:

magnetic field will allow the electron to go through 2 x 10^{4}  T k

Explanation:

Given data in question

velocity = 5.0 × 10^{7}

electric filed = 10^{4}

To find out

what magnetic field will allow the electron to go through, undeflected

solution

we know if electron move without deflection i.e. net force is zero on electron and we can say both electric and magnetic force equal in magnitude and opposite in directions

so we can also say

F(net) = Fe + Fb i.e. = 0

q V B +  q E = 0

q will be cancel out

10^{4}j + 5e + 7i × B =  0

B = 2 x 10^{4}  T k

3 0
3 years ago
Help me?!?!?!?!?!?!?!?!?!?!?!?!?!
marishachu [46]
The correct field line would be A.
3 0
3 years ago
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Lorico [155]
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3 0
3 years ago
Read 2 more answers
Block A of 5 kg with a speed of 3 m/s collides with block B of 10 kg that is stationary. After the collision, block B travels wi
Lemur [1.5K]

Answer:

-1m/s

Explanation:

We can calculate the speed of block A after collision

According to collision theory:

MaVa+MbVb = MaVa+MbVb (after collision)

Substitute the given values

5(3)+10(0) = 5Va+10(2)

15+0 = 5Va + 20

5Va = 15-20

5Va = -5

Va = -5/5

Va = -1m/s

Hence the velocity of ball A after collision is -1m/s

Note that the velocity of block B is zero before collision since it is stationary

6 0
3 years ago
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