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Marizza181 [45]
2 years ago
5

Q2. A certain machine is used to lift a load of 500N when an effort of 50N is applied to the machine the load is raised by 10m a

nd effort is moved by 60m that is the efficiency of the machine? (1. sp)​
Physics
2 answers:
Natalija [7]2 years ago
8 0

Answer:

2%

Explanation:

E=l/E x r/R x100%

=5000/50 x 0.1/0.6 x100

=2% or 166.7

White raven [17]2 years ago
6 0
Answer:
166.667%
Explanation:
MA = 500/50
. = 10
VR=60/10
=6
Efficiency=10/6 X 100%
=166.667
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List the submultiples and multiple units of length, mass, and time with respect to real-life situations. How are these units are
dangina [55]

Answer:

Explanation:

In physics, there are two types of physical quantities namely the fundamental and the derived quantities. Fundamental quantities are independent quantities on which derived quantities depends on. Length, mass and time are examples of fundamental quantities.

The SI unit of length is meters. A meter is a multiple unit. Its submultiple units are centimetres (10⁻²metres), kilometres (10³metres), decimetres (10⁻¹metres) etc

The SI unit of mass is kilogram (kg). The only sub multiple unit used in real-life situation is grams.

1 kg = 100 grams

The SI unit of time is seconds. The multiple units are the minutes, hours, weeks, days and years.

1 minute = 60 seconds

1 hour = 3600 seconds

1 day = 24 * 3600 = 86,400 secs

4 0
2 years ago
High and low tides are the regular pattern of rising and sinking ocean-water levels. They are caused when the sun's gravity and
MrRa [10]

Answer:

D. The moon is closer to Earth than the sun.

Explanation:

Tides are formed as a consequence of the differentiation of gravity due to the moon across to the Earth sphere.

Since gravity variate with the distance:

   

F = G\frac{m1\cdot m2}{r^{2}}  (1)                            

Where m1 and m2 are the masses of the two objects that are interacting and r is the distance

For example, see the image below, point A is closer to the moon than point b and at the same time the center of mass of the Earth will feel more attracted to the moon than point B. Therefore, that creates a tidal bulge in point A and point B.

The Sun tidal force contributes to the tidal force of the moon over the earth making high tides higher and low tides lower.  

However, even when the sun is more massive than the moon, it is farther away from the Earth than the moon. So, it is clear by equation 1 that the moon's gravity has a greater effect on Earth's oceans than the sun's gravity.         

8 0
3 years ago
If you make an electromagnet using a battery circuit and a steel nail, how can you increase its magnetic strength?
madam [21]
B. Wrap more coils of wire around the nail
Increasing the number of coils in an electromagnet increases the strength of the magnetic field.
4 0
3 years ago
Read 2 more answers
A net force of 10.0 N causes an object to accelerate at 2.00m/s^2. What is the mass of the object?
madam [21]

5.00kg

random = abcdefghijklmnopqrstuvwxyz


4 0
3 years ago
A rocket has landed on planet x, which has half the radius of earth. An astronaut onboard the rocket weighs twice as much on pla
Nastasia [14]

Answer:

Option (c) u0

Explanation:

The escape velocity has a formula as:

V = √(2gR)

Where V is the escape velocity,

g is the acceleration due to gravity

R is the radius of the earth.

Now, from the question, we were told that the escape velocity for the rocket taking off from earth is u0 i.e

V(earth) = u0

V(earth) = √(2gR)

u0 = √(2gR) => For the earth

Now, let us calculate the escape velocity for the rocket taking off from planet x. This is illustrated below below:

g(planet x) = 2g (earth) => since the weight of the astronaut is twice as much on planet x as on earth

R(planet x) = 1/2 R(earth) => planet x has half the radius of earth

V(planet x) =?

Applying the formula V = √(2gR), the escape velocity on planet x is obtained as follow:

V(planet x) = √(2g(x) x R(x))

V(planet x) = √(2 x 2g x 1/2R)

V(planet x) = √(2 x g x R)

V(planet x) = √(2gR)

The expression obtained for the escape velocity on planet x i.e V(planet x) = √(2gR), is exactly the same as that obtained for the earth i.e V(earth) = √(2gR)

Therefore,

V(planet x) = V(earth) = √(2gR)

But from the question, V(earth) is u0

Therefore,

V(planet x) = V(earth) = √(2gR) = u0

So, the escape velocity on planet x is u0

4 0
3 years ago
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