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Anna [14]
3 years ago
9

If the pH of a solution is 7.6, what is the pOH? A. 6.4 B. 8.4 C. 5.4 D. 7.4

Chemistry
1 answer:
maks197457 [2]3 years ago
8 0

Answer:

6.4

 

Explanation:  pH

+

pOH

=

14

So if  

pH

=

7.6

then  

pOH

=

14

−

pH

=

6.4

Explanation:

Wrote this out spaced so it's more clear.

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The following pieces of evidence were found at separate explosion sites. For each item, indicate whether the explosion was more
tangare [24]

Explanation:

The major difference between low and high explosives is the rate of detonation. Low explosives detonate very slowly (less than 1,000 meters per second), whereas high explosives detonate very quickly (from 1,000 to 8,500 meters per second).

High explosives among the given list are Lead azide residues, Ammonium nitrate residues, and  Scraps of primacord. Whereas Nitrocellulose residues and, Potassium chlorate residues are low explosives.

7 0
3 years ago
In an acid-base titration experiment, 50 mL of a 0.05 M solution of acetic acid (Ka= 1.75 x 10-5 ) was titrated with a 0.05M sol
Viktor [21]

Answer:

(3) 5.36

Explanation:

Since this is a titration of a weak acid before reaching equivalence point, we will have effectively a buffer solution. Then we can use the Henderson-Hasselbalch equation to answer this question.

The reaction is:

HAc + NaOH ⇒ NaAc + H₂O

V NaOH = 40 mL x 1 L/1000 mL = 0.040 L

mol NaOH reacted with HAc = 0.040 L x 0.05 mol/L = 0.002 mol

mol HAC originally present = 0.050 L x 0.05 mol/L = 0.0025 mol

mol HAc left after reaction = 0.0025 - 0.002 = 0.0005

Now that we have calculated the quantities of the weak acid and its conjugate base in the buffer, we just plug the values into the equation

pH = pKa + log ((Ac⁻)/(HAc))

(Notice we do not have to calculate the molarities of  Ac⁻ and HAc because the volumes cancel in the quotient)

pH = -log (1.75 x 10⁻⁵) + log (0.002/0.0005) = 5.36

THe answer is 5.36

5 0
3 years ago
Read 2 more answers
40.0L of N₂ gas are in a sealed container at STP.How many moles of N₂ are present?9 mol
Vinvika [58]

Explanation:

We have to find the number of moles of N₂ that are present in a sample that has a volume of 40.0 L at STP.

STP means Standard Conditions of Temperature and Pressure. These conditions are 273.15 K and 1 atm. We know that 1 mol of N₂ will occupy 22.4 L. We can use that ratio to find the answer to our problem.

1 mol of N₂ = 22.4 L

moles of N₂ = 40.0 L * 1 mol/(22.4 L)

moles of N₂ = 1.79 mol

Answer: 1.79 moles of nitrogen are present.

8 0
1 year ago
tate whether the following changes are physical or chemical for rancidipication fixation of water 2 tearing of paper 3 rusting o
damaskus [11]

Answer: Physical change : tearing of paper, fixing of wtaer

Chemical change:  rusting of iron ,  electrolysis of water​, Rancidification

Explanation:

Physical change is a change in which there is no rearrangement of atoms and thus no new substance is formed. There is only change in physical state of the substance.

Example:  tearing of paper, fixing of wtaer

Chemical change is a change in which there is rearrangement of atoms and thus new substance is formed. There may or may not be a change in physical state.

Example: rusting of iron ,  electrolysis of water​, Rancidification

3 0
3 years ago
Whats the molar mass of potassium nitride
Lyrx [107]
<span>The answer is
101.1032 g/mol</span>
6 0
4 years ago
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