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aalyn [17]
3 years ago
9

Which of the following equations demonstrates an actual chemical reaction that forms a new substance? A.ZN + 2HCl → 2NCl2 + H2 B

.H2O + NaCl → H2O C.Zn + Al + Cu → Zn + Cu + Al D.C12H22O11 + H2O → H2O + C12H22O11
Chemistry
1 answer:
alukav5142 [94]3 years ago
6 0

Answer:

A

Explanation:

The first option is the only option where new products are formed.

In the D option no new product is formed.

Same goes with option C.

In B no new products are formed.

Change is said to be taken place only with formation of new products from reactants.

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sp2606 [1]
The answer is an atom.
4 0
3 years ago
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calculate q for the following: 125.0 ml of 0.0500 m pb(no3)2 is mixed with 75.0 ml of 0.0200 m nacl at 25oc chegg
alexandr402 [8]

The value of Q for 125.0 ml of 0.0500 m Pb(NO3)2 is mixed with 75.0 ml of 0.0200 m NaCl at 25°C is 2.11 × 10^(-6).

Aa we know that, 125mL of 0.06M Pb(NO3)2 is mixed with 75.0 ml of 0.0200 m NaCl.

Given, T = 25°C.

<h3>Chemical equation:</h3>

Pb(NO3)2 + NaCl ---- NaNO3 + PbCl2

PbCl2 in aqueous solution split into following ions

PbCl2 ------ Pb(+2) + 2Cl-

Q = [Pb(+2)] [Cl-]^2

The Concentration of Pb(+2) ions and Cl- ions can be calculated as

[Pb(+2)] = 0.06 × 125/200

= 0.0375

[Cl-] = 0.02 × 75/200

= 0.0075

By substituting all the values, we get

[0.0375] [0.0075]^2

= 2.11 × 10^(-6).

Thus, we calculated that the value of Q for 125.0 ml of 0.0500 m Pb(NO3)2 is mixed with 75.0 ml of 0.0200 m NaCl at 25°C is 2.11 × 10^(-6).

learn more about Ions:

brainly.com/question/13692734

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6 0
2 years ago
Besides water, what is the product of a Neutalization Reaction between HBr and CsOH?
Luba_88 [7]
I don’t know dawg but I’m just answering this so I can complete the steps good luck tho
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Oxana [17]

Answer:

A Bronsted-Lowry acid like and Arrhenius acid is a compound that breaks down to give an H+ in solution. The only difference is that the solution does not have to be water. ... An Arrhenius base is a molecule that when dissolved in water will break down to yield an OH- or hydroxide in solution.

Explanation:

7 0
3 years ago
with strong heating calcium carbonate undergoes thermal decomposition how many mole of CaCO3 are there in 50g of calcium carbona
aev [14]
Ca=40
C=12
O=16
1 mole of CaCO3 has 100 grams
So 50 grams is 0.5 mole
6 0
2 years ago
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