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aalyn [17]
3 years ago
9

Which of the following equations demonstrates an actual chemical reaction that forms a new substance? A.ZN + 2HCl → 2NCl2 + H2 B

.H2O + NaCl → H2O C.Zn + Al + Cu → Zn + Cu + Al D.C12H22O11 + H2O → H2O + C12H22O11
Chemistry
1 answer:
alukav5142 [94]3 years ago
6 0

Answer:

A

Explanation:

The first option is the only option where new products are formed.

In the D option no new product is formed.

Same goes with option C.

In B no new products are formed.

Change is said to be taken place only with formation of new products from reactants.

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Give the Unabbreviated electron configuration for barium
Shalnov [3]

Answer:

Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

Step-by-step explanation:

Step 1. Locate barium in the Periodic Table.

It's in Period 6, Group 2: Element 56 (highlighted blue in the Periodic Table below).

Step 2. Add 54 electrons to the energy levels

You add then in the order shown in the diagram below.

The complete electron configuration is:

Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

n =  2 +     8    +    8     +       18       +       18       +  2 = 56

8 0
3 years ago
What kind of bond is N and C
yKpoI14uk [10]
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4 0
2 years ago
What are the effects on global food webs if the sun's energy could no longer reach Earth
gogolik [260]
They would collapse as the sun gives the producers energy to grow i.e plants through photosynthesis. Without plants most animals would die out unless humans could somehow create a food in labs without animals or plants for 6 billion people. Ultimately it would be the death of the human race and just about everything on Earth apart from some plants that live in the deep depths of the sea which have adapted to not having as much sunlight. 
6 0
2 years ago
Find the wavelength of the electromagnetic radiation with a frequency of 3.52x10^-22J PLEASE HELPPP!!!
LuckyWell [14K]

Answer:

λ   = 0.85×10³⁰ m

Explanation:

Given data:

Wavelength of radiation =  ?

Frequency of radiation = 3.52×10⁻²² Hz

Solution:

Formula:

c = f × λ

c = speed of wave = 3×10⁸ m/s

by putting values,

3×10⁸ m/s =  3.52×10⁻²² Hz × λ

λ  =  3×10⁸ m/s / 3.52×10⁻²² s⁻¹

λ   = 0.85×10³⁰ m

8 0
2 years ago
Nicotine is an addictive substance found in tobacco. Identify the hybridization state and geometry of each of the nitrogen atoms
Marina CMI [18]

The structure of nicotine is as follows:

In the aromatic ring, nitrogen atom has two bonds and one lone pair therefore, hybridization will be sp^{2}. In five-membered ring , nitrogen has two bonds and 1 lone pair therefore, hybridization will be sp^{3}.

Therefore, hybridization state of N^{1} and N^{2} (as in the attached structure) is sp^{2} and sp^{3} respectively.

Now, according to VESPR theory for sp^{2} hybridization with one lone pair the geometry is bent and for sp^{3} hybridization with one lone pair the geometry is pyramidal.

Therefore, geometry of N^{1} and N^{2} (as in the attached structure) is bent and pyramidal respectively.

3 0
3 years ago
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