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NNADVOKAT [17]
3 years ago
14

How has СOVID-19 demonstrated the process of the scientific method for the public?

Chemistry
1 answer:
Vesnalui [34]3 years ago
7 0

Answer:

none

Explanation:

none

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Which of the following environments is most likely to have days with a relative humidity of less than 10% (ten percent)?
Anon25 [30]

Answer:

Desert

Explanation:

Desert barely have any water therefore they can barely produce any amount of humidity

6 0
3 years ago
Anyone know ?? I need help with this
nevsk [136]

Answer:

A

Explanation:

Because the amount of electrons in the outer shell can be a maximum of 8

Hope this helps

6 0
3 years ago
I just need help plz!
Nesterboy [21]

Answer:

<u>Graphene</u> is a nanomaterial that is often used with other compounds to desalinate and decontaminate water.

The electrical behavior of semiconductor devices and electronics can be engineered using a process called <u>Doping</u>

Explanation:

4 0
2 years ago
A generator does work on an electric heater by forcing an electric current through it. Suppose 1 kJ of work is done on the heate
azamat

Answer:

The change in internal energy of the heater is 0 kJ

Explanation:

∆U = Q - W

Q is quantity of heat transferred = 1 kJ

W is work done on the heater = 1 kJ

Change in internal energy (∆U) = 1 - 1 = 0 kJ

3 0
3 years ago
Read 2 more answers
When 74.8g of alanine C3H7NO2 are dissolved in 1450.g of a certain mystery liquid X, the freezing point of the solution is 8.30°
dlinn [17]

Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.30^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant =  

m= molality = \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}=\frac{74.8g\times 1000}{1450g\times 89.09g/mol}=0.579

8.30^0C=1\times K_f\times 0.579

K_f=14.3^0C/m

Let Mass of solute (KBr) = x g

8.3^0C=1.72\times 14.3\times \frac{xg\times 1000}{119g/mol\times 1450g}

x=58.2g

Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

7 0
2 years ago
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