All categories

3 years ago

For a 0.00554 mol sample of H2, P=23.44 torr and T=557 K. What is its volume?

Chemistry

1 answer:

Vitek1552 [10]3 years ago

5 0

Answer:

The volume is 8,22 liters.

Explanation:

The unit of pressure (from Torr to atm) must be converted: 760 Torr = 1 atm

760 Torr---1 atm

23,44Torr--x= (23,44Torr x 1 atm)/760 Torr= 0,0308 atm

PV=nRT V= (nRT)/P

V=(0,00554 mol x 0,082 l atm/K mol x 557 K)/ 0,0308 atm

V=8, 22 L

You might be interested in

Can someone please help me? :(

Dmitriy789 [7]

Answer:

Trade winds

Explanation:

I am not sure

7 0

2 years ago

30 pts! Sodium and water react according to the following equation. If 31.5g of sodium are added to excess water, how many liter

mihalych1998 [28]

First, calculate the number of moles of sodium present with the given mass,

31.5 g of sodium x (1 mol sodium/ 23 g sodium) = 1.37 mol sodium

It is given in the equation that for every 2mols of sodium, one mol of H2 is produced.

mols of H2 = (1.37 mols sodium)(1 mol H2/ 2 mols sodium)
mols of H2 = 0.685 mols H2

Then, at STP, 1 mol of gas = 22.4 L.

volume of H2 = (0.685 mols H2)(22.4 L / 1 mol)
volume of H2 = 15.34 L

Answer: 15.34 L

3 0

4 years ago

Under what pressure did 10L of gas change to if the original pressure was 4 atm on 3L?

cluponka [151]

Answer:

11111

Explanation:

1110001001

3 0

3 years ago

2. Calculate the number-average molecular weight of a random poly (isobutylene-isoprene) copolymer in which the fraction of isob

Phoenix [80]

Answer : The number-average molecular weight is, 97500 g/mol

Explanation :

First we have to calculate the molecular weight of isobutylene and isoprene.

The molecular formula of isobutylene and isoprene is, $C_4H_8$ and $C_5H_8$

Molecular weight of $C_4H_8$ = 4(12 g//mol) + 8(1 g/mol) = 56 g/mol

Molecular weight of $C_5H_8$ = 5(12 g//mol) + 8(1 g/mol) = 68 g/mol

Now we have to calculate the average repeat molecular weight.

Average repeat molecular weight = $0.25\times (56g/mol)+(1-0.25)\times (68g/mol)$

Average repeat molecular weight = 65 g/mol

Now we have to calculate the number-average molecular weight.

Number-average molecular weight = Average repeat molecular weight × Degree of polymerization

Number-average molecular weight = (65 g/mol) × (1500)

Number-average molecular weight = 97500 g/mol

Thus, the number-average molecular weight is, 97500 g/mol

5 0

3 years ago

At a certain temperature and pressure, 0.20 mol of carbon dioxide has a volume of 3.1 L. A 3.1-L sample of hydrogen at the same

Arada [10]

A 3.1 L sample of hydrogen d. contains the same number of molecules

as 3.1 L of carbon dioxide at the same temperature and pressure.

This is the fundamental principle of Avogadro’s hypothesis: equal volume of gases at the same temperature and pressure contain the same number of molecules.

The sample of carbon dioxide has a greater mass, a greater number of atoms, and a greater density, than the sample of hydrogen.

7 0

3 years ago