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DanielleElmas [232]
1 year ago
9

Sulfur and fluorine react in a combination reaction to produce sulfur hexafluoride:

Chemistry
1 answer:
mixer [17]1 year ago
3 0

In a particular experiment, the per cent yield is 79.0%. This means that in this experiment, a 7.90-g sample of fluorine yields is 7g of SF6.

<h3>How is Sulphur hexafluoride formed?</h3>

Sulfur Hexafluoride is a disparity agent formed of an inorganic fluorinated inert gas comprised of six fluoride atoms bound to one sulfur atom, with possible diagnostic activity upon imaging.

Thus, a sample of fluorine yields 7g of SF6.

To learn more about Sulfur Hexafluoride click here;

brainly.com/question/15024952

#SPJ1

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Properties of matter with three example each
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Answer:

Extensive properties vary with the amount of the substance and include mass, weight, and volume. Intensive properties, in contrast, do not depend on the amount of the substance; they include color, melting point, boiling point, electrical conductivity, and physical state at a given temperature.

8 0
3 years ago
If normal rainwater has a pH of about 6.50, what is the hydrogen ion concentration, [H+]?
IceJOKER [234]

Answer:

.000000316

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6 0
3 years ago
Justin mixed two clear liquids together during an experiment and made the following observations: The mixed liquids decreased in
kvasek [131]

Answer:

B

Explanation:

A chemical change occurred, and this caused the liquid’s physical properties to change.

when we read her experiment we can see that color changed to blue, it is because new products are formed. And the temperature cause this.

5 0
2 years ago
What is the electric field (in N/C) at a point 5.0 cm from the negative charge and along the line between the two charges?
Natali [406]

Answer: E = 2.455 x 10^5 N/C

Explanation:

q1 = 1.2x10^-7C

q2 = 6.2x10^-8C

Electric field, E = kQ/r²

where k = 9.0x10^9

since the location is (27 - 5)cm from q1

hence electric field, E1 = k*q1/r²

E1= (9x10^9 x 1.2x10^-7)/(0.22)² = 22314.05 N/C

for q2:

E1 = k*q2/r²

E2 at 5cm

E2 = (9x10^9 x 6.2x10^-8)/(0.05)² = 223200 N/C

Hence, the total electric field at 5cm position is

E = E1 + E2

E = 22314.05 + 223200 = 245514.05 N/C

E = 2.455 x 10^5 N/C

4 0
3 years ago
Use the limiting reagent to determine how many grams of Cu(OH)2 should precipitate out in the reaction - CuSo4(aq) + 2NaOH(aq) -
Elis [28]
I think there is a lack of information in the given problem above such as the grams of copper sulfate and sodium hydroxide that was used in the experiment. Kindly resubmit the question with the complete details so that we can help you. Thank you.

7 0
2 years ago
Read 2 more answers
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