The number of grams of carbon that combine with 16 g of oxygen in the formation of CO₂ is 6g.
When two elements combine to make more than one compound, the masses of one element combined with a fixed amount of another element are in the ratio of whole numbers, according to the law of multiple proportions.
When combined with oxygen, carbon can produce two different compounds. They are referred to as carbon dioxide (CO₂) and carbon monoxide (CO).
Carbon monoxide is formed by combining 12 g of carbon with 16 g of oxygen whereas Carbon dioxide is formed when 12 g of carbon reacts with 32 g of oxygen. The amount of carbon is fixed at 12 g in each case. The mass ratio of carbon monoxide to carbon dioxide is 16: 32, or 1: 2.
But in the given case, 16g of oxygen is reacting instead of 32g. Therefore, the number of grams of carbon reacting will be:
Thus, 6g of carbon will react with 16g of oxygen to form carbon dioxide.
Read more about Law of Multiple Proportions:
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Answer:
The answer to your question is when time = 50 s, work = 5000 J
when time = 90 s, work = 9000 J
Explanation:
Data
time = 50 s or 90 s
Power = 100 watts
Power is defined as the rate of work done per unit of time.
Power = Work / time
-Solve for Work
Work = Power x time
-Substitution
Work = 100 x 50
-Result
Work = 5000
2.-When time = 90 s
Work = 100 x 90
-Result
Work = 9000 watts
The breaking distance consists of two parts. The first part is the first 0.5 seconds were no breaking occurs. Given values: t time, v₀ initial velocity:
x₁ = v₀*t
The second part occurs after t = 0,5s with the given acceleration: a = - 12 m/s²
were the final velocity is zero, v = 0 and the initial velocity v₀= 16m/s:
v = a*t + v₀ = 0 => v₀ = -a*t => t = v₀/-a
x₂ = 0.5*a*t² = 0.5*v°²/a
The total breaking distance is the sum of the two parts:
x = x₁ + x₂ = v₀* t + 0.5 * v₀² / a = 16 * 0.5 + 0.5 * 16² / 12 = 8 + 10,7 = 18,7
You can use this result to calculate the remaining distance. You can use the last equation to calculate the maximum speed you could have to avoid a collision.
Use x = 39m and solve for v₀.
The spider is traveling in a circle with radius = 15cm
The circumference of any circle = <em>2 pi (radius)</em>
The circumference of the spider's path = 2 pi (15 cm) = 30 pi cm
The spider completes a trip around this path 78 times per minute.
Its speed, relative to you, is
(78) x (30 pi) cm/min =
2,340 pi cm/min = 7,351.33 cm/min =
<em> 73.5133 meter/min =</em>
<em>4.411 km/hr =</em>
<em>2.74 miles/hour
</em>(After the last appearance of pi,
all numbers are rounded.)<em>
</em>
Answer:
280 N
Explanation:
acceleration = v2-v1 / time taken = (2-4 )/ 0.05 = -40 m/s^2 ( neg sign indicates slowing down )
force exerted = ma = 7 kg x -40 m/s^2 = - 280 N ( neg sign means opposite direction of initial velocity )
since the 7 kg ball is slowing down, the direction of force will be opposite of the initial velocity , and it will be 280 N
