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RideAnS [48]
3 years ago
15

A flagpole consists of a flexible, 7.107.10 m tall fiberglass pole planted in concrete. The bottom end of the flagpole is fixed

in position, but the top end of the flagpole is free to move. What is the lowest frequency standing wave that can be formed on the flagpole if the wave propagation speed in the fiberglass is 27302730 m/s?
Physics
1 answer:
vladimir1956 [14]3 years ago
3 0

To develop this problem we require the concepts related to Frequency and their respective way of calculating it.

The formula to calculate the frequency is given by

f=\frac{V}{\lambda}

Where,

\lambda = wavelength

V= velocity

For fundamental mode, wavelength is equal to 4 time the length.

Then,

\lambda = 4L = 4*7.10m=28.4m

Replacing in the first equation,

f=\frac{2730}{28.4}\\

f= 96.12Hz

Therefore the frequency is 96.12Hz

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shows a conical pendulum, in which the bob (the small object at the lower end of the cord) moves in a horizontal circle at const
Contact [7]

Answer:

a) T=0.40 N

b) T=1.9 s

Explanation:

Let's find the radius of the circumference first. We know that bob follows a circular path of circumference 0.94 m, it means that the perimeter is 0.94 m.

The perimeter of a circunference is:

P=2\pi r=0.94

r=\frac{0.94}{2\pi}=0.15 m

Now, we need to find the angle of the pendulum from vertical.

tan(\alpha)=\frac{r}{L}=\frac{0.15}{0.90}=0.17

\alpha=9.44 ^{\circ}

Let's apply Newton's second law to find the tension.

\sum F=ma_{c}=m\omega^{2}r

We use centripetal acceleration here, because we have a circular motion.

The vertical equation of motion will be:

Tcos(\alpha)=mg (1)

The horizontal equation of motion will be:

Tsin(\alpha)=m\omega^{2}r (2)

a) We can find T usinf the equation (1):

T=\frac {mg}{cos(\alpha)}=\frac{0.04*9.81}{cos(9.44)}=0.40 N

We can find the angular velocity (ω) from the equation (2):

\omega=\sqrt{\frac{Tsin(\alpha)}{mr}}=3.31 rad/s

b) We know that the period is T=2π/ω, therefore:

T=\frac{2\pi}{\omega}=\frac{2\pi}{3.31}=1.9 s

I hope it helps you!

8 0
3 years ago
A research submarine has a 30-cm-diameter window that is 8.1 cm thick. The manufacturer says the window can withstand forces up
malfutka [58]

The pressure at a certain depth underwater is:

P = ρgh

P = pressure, ρ = sea water density, g = gravitational acceleration near Earth, h = depth

The pressure exerted on the submarine window is:

P = F/A

P = pressure, F = force, A = area

The area of the circular submarine window is:

A = π(d/2)²

A = area, d = diameter

Set the expressions for the pressure equal to each other:

F/A = ρgh

Substitute A:

F/(π(d/2)²) = ρgh

Isolate h:

h = F/(ρgπ(d/2)²)

Given values:

F = 1.1×10⁶N

ρ = 1030kg/m³ (pulled from a Google search)

g = 9.81m/s²

d = 30×10⁻²m

Plug in and solve for h:

h = 1.1×10⁶/(1030(9.81)π(30×10⁻²/2)²)

h = 1540m

5 0
3 years ago
A lithium atom has three protons, three neutrons, and three electrons. What is the overall charge on this atom?
Marizza181 [45]

Answer:

0

Explanation:

The overall charge on this atom is 0.

  To find the charge on an atom;

           charge  = number of protons - number of electrons.

Note:

  • Protons are the positively charged particles in an atom
  • Electrons are the negatively charged particles in an atom
  • Neutrons carries no charges on them.

Since the atom is made up of equal number of protons and electrons, the charge on it is 0.

If the number of electrons is more, the atom will be negatively charge but if the number of protons is more, it will be positively charged.

8 0
3 years ago
Read 2 more answers
EASY MULTIPLE CHOICE QUESTIONS! PLEASE HELP!
skad [1K]
1.A and 2.B there the answers
8 0
3 years ago
which of the following cannot be increased by using a machine of some kind? work, force, speed, torque
Lemur [1.5K]

Explanation:

Work cannot be increased by using a machine of some kind.

8 0
3 years ago
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