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RideAnS [48]
3 years ago
15

A flagpole consists of a flexible, 7.107.10 m tall fiberglass pole planted in concrete. The bottom end of the flagpole is fixed

in position, but the top end of the flagpole is free to move. What is the lowest frequency standing wave that can be formed on the flagpole if the wave propagation speed in the fiberglass is 27302730 m/s?
Physics
1 answer:
vladimir1956 [14]3 years ago
3 0

To develop this problem we require the concepts related to Frequency and their respective way of calculating it.

The formula to calculate the frequency is given by

f=\frac{V}{\lambda}

Where,

\lambda = wavelength

V= velocity

For fundamental mode, wavelength is equal to 4 time the length.

Then,

\lambda = 4L = 4*7.10m=28.4m

Replacing in the first equation,

f=\frac{2730}{28.4}\\

f= 96.12Hz

Therefore the frequency is 96.12Hz

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For a sinusoidal wave, the power is proportional to the square of the amplitude, so the intensity is proportional to the square of the amplitude also.

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