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creativ13 [48]
2 years ago
6

On a hot day, the deck of a small ship reaches a temperature of 48

Physics
1 answer:
AlekseyPX2 years ago
6 0

The final temperature of the seawater-deck system is 990°C.

<h3>What is heat?</h3>

The increment in temperature adds up the thermal energy into the object. This energy is Heat energy.

The deck of a small ship reaches a temperature Ti= 48.17°C seawater on the deck to cool it down. During the cooling, heat Q =3,710,000 J are transferred to the seawater from the deck. Specific heat of seawater= 3,930 J/kg°C.

Suppose for 1 kg of sea water, the heat transferred from the system is given by

3,710,000 = 1 x 3,930 x (T - 48.17)

T = 990°C  to the nearest tenth.

The final temperature of the seawater-deck system is 990°C.

Learn more about heat.

brainly.com/question/13860901

#SPJ1

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What is the range of a 10k ohm potentiometer?
musickatia [10]
Its gotta be 7k bc that's what it adds up too
4 0
4 years ago
1. How much force would you have to apply to a 15kg object in order to accelerate it!<br> a 2 m/s?
mihalych1998 [28]

30N

Explanation:

Given parameters:

Mass of object = 15kg

Acceleration = 2m/s

Unknown:

Force = ?

Solution:

Force is given as the product of mass and acceleration:

         F = m x a

   m is the mass

    a is the acceleration

Inputting the parameters:

     F = 15 x 2 = 30N

The unit of force is newtons, N .

Learn more:

Force brainly.com/question/10470406

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3 0
3 years ago
A force F acting on an object of mass m causes a displacement d. The angle between these two vectors is Θ. The work W done on th
777dan777 [17]
Work:
W= \int\limits^b_a {F.} \, ds

F: force
ds: displacement

Assuming the work is constant:

W= \int\limits^b_a {F.} \, ds =  F . d = F * cos\theta * d

d displacement


4 0
3 years ago
Part e a small toy cart equipped with a spring bumper rolls toward a wall with a speed of v. the cart rebounds from the wall, wi
jeka94

Answer:

Δp = -2 p₀

Explanation:

The momentum is defined by

         p = m v

In this case we write the initial and final momentum, we take as positive the direction towards the wall.

         p₀ = m v

         p_f = m (-v)

the negative sign is because the car is bouncing off the wall

the change of the moment is

       Δp = p_f - p₀

        Δp = - m v - m v

        Δp = -2 mv

        Δp = -2 p₀

we see that the change of moment is twice the moment, in the attachment we can see the vectors of these changes and the sign indicates the direction of the change at the moment

5 0
3 years ago
Find the eastward component of 50 m/s 25º north of east. <br> NEED HELP ASAP!
jeyben [28]

The speed of the object is the rate where it changes position relative to the frame of reference. The speed equates to a stipulated speed and motion direction of the item, and the further calculation can be defined as follows:

Given:

\bold{\theta = 25^{\circ}}\\\\\bold{Velocity= 50\ \frac{m}{s}}\\\\

To find:

Find the eastward component=?

Solution:

When the angle is north-east, the angle is the east measured

Using formula:

\bold{\text{eastward component = (velocity)}\times \cos \theta}}

                                 = \bold{50 \times \cos 25^{\circ} }\\\\= \bold{50 \times 0.90631 }\\\\=\bold{45.3155 \ \frac{m}{s}}

So, the final answer is "45.3155 m/s".

Learn more:

brainly.com/question/19040795

8 0
2 years ago
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