Question

Una carga de 4 uC penetra perpendicularmente en un campo magnetico de 0.4 T con una velocidad de 7.5x10 4 m/s. Calcular la fuerza que recibe la carga

Answer 1

Answer:

F_B = 0.12N

Explanation:

In order to calculate the magnetic force on the charge, you use the following formula:

$\vec{F_B}=q\vec{v}\ X\ \vec{B}$          (1)

q: charge of the particle = 4μC = 4*10^-6 C

v: speed of the charge = 7.5*10^4 m/s

B: magnitude of the magnetic field = 0.4T

The direction of the motion of the charge is perpendicular to the direction of the magnetic field. Then, the magnitude of the magnetic force is:

$F_B=qvBsin90\°\\\\F_B=(4*10^{-6}C)(7.5*10^4 m/s)(0.4T)=0.12N$

The magnetic force on the charge is 0.12N