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Ksivusya [100]
3 years ago
10

Hdhehehbebehebehebebbebehe

Physics
2 answers:
Neko [114]3 years ago
7 0
Describe your Cøvid experience in two or one sentence
qaws [65]3 years ago
5 0

Answer:

Is this suppose to be a question?

Explanation:

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3 years ago
A silver wire with resistivity 1.59 × 10-8 Ω-m carries a current density of 4.0 A/mm2, What is the magnitude of the electric fie
Nat2105 [25]

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Electric field, E = 0.064 V/m

Explanation:

It is given that,

Resistivity of silver wire, \rho=1.59\times 10^{-8}\ \Omega-m

Current density of the wire, J=4\ A/mm^2=4\times 10^6\ A/m^2

We need to find the magnitude of the electric field inside the wire. The relationship between electric field and the current density is given by :

E=J\times \rho

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