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Alika [10]
3 years ago
12

Which postulate or theorem proves △FWJ∼△PKJ ?

Mathematics
2 answers:
iogann1982 [59]3 years ago
7 0

Answer:

Aa SIMILARITY POSTUALTE SHOULD BE THE ANSWER

Step-by-step explanation:

artcher [175]3 years ago
4 0

AA Similarity Postulate - we get the triangle on the left's angles; 90 and 63, and we subtract from 180.

180 - 90 - 63 = 27

So we have angle measures 27, 63, 90

For the triangle on the right, with measures 27 and 90, we use the same  idea:

180 - 90 - 27 = 63.

You'll see that we also have 27, 63, 90.

Triangles with the same angles are defined as similar, so AA should be the answer

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!28 POINTS! I need help quick!! The area of a rectangle is 2x^2-7x-15. Determine binomials that represent the length and the wid
Fudgin [204]

Answer:

(2x +3  )(x-5)

one is the length and one is the width

Step-by-step explanation:

2x^2-7x-15

Factor

(2x      )(x      )

What are the factors of -15?  -1*15  and -3*5, 3*-5 , 1*-15

We need 2* one factor ± the other factor = -7

2*-5 +3 = -7

That means the -5 is on the outside and the +3 is on the inside

(2x +3  )(x-5)

3 0
3 years ago
Dada una distribución t de Student con 15 grados de libertad, calcule el valor de t1 tal que a) el área a la derecha de t1 sea 0
nikitadnepr [17]

Answer:

a)  t₁ = 2,947

b)  t₁ = 2,131

c)  t₁ = 1,753

d) t₁ = 2,947   -t₁ = -2,947  

e) t₁ = 2,131    -t₁  = -2, 131

Step-by-step explanation:

a) t₁ para el área a la derecha de 0,01  

En la tabla t- student  el t correspondiente a 0,01  es:

t₁ = 2,947

b) t₁ para el área a la izquierda sea de 0,95. Es igual al t para el cual el área de la drecha es  0,05

t₁ = 2,131

c) t₁ para que el área de la derecha sea 0,10

t₁ = 1,753

d) Buscar t₁ para el cual las áreas de derecha de (t₁) más la de la izquierda  de (- t₁ ) sea  0,01.

Si el área es de 0,01 quere decir que la mitad, es decir 0,005 es el área para una cola, luego

t₁ = 2,947  y -t₁ = -2,947

e) Para que el área entre - t₁ y t₁ sea 0,95

t₁ = 2,131  y  -t₁  = -2, 131

6 0
3 years ago
The sum of two integers is 66. The larger is 12 less than five times the smaller. Find the two integers
VikaD [51]

Answer:

13 and 53

Step-by-step explanation:

First Integer: x

Larger integer: 5x-12

66=x+(5x-12)

66= x+5x-12

66=6x+12

78=6x

13=x

First Integer: 13

Larger Integer: 13*5-12= 65-12=53

Check Work:

13+53=66

4 0
3 years ago
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wolverine [178]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

4 0
3 years ago
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