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Alika [10]
3 years ago
12

Which postulate or theorem proves △FWJ∼△PKJ ?

Mathematics
2 answers:
iogann1982 [59]3 years ago
7 0

Answer:

Aa SIMILARITY POSTUALTE SHOULD BE THE ANSWER

Step-by-step explanation:

artcher [175]3 years ago
4 0

AA Similarity Postulate - we get the triangle on the left's angles; 90 and 63, and we subtract from 180.

180 - 90 - 63 = 27

So we have angle measures 27, 63, 90

For the triangle on the right, with measures 27 and 90, we use the same  idea:

180 - 90 - 27 = 63.

You'll see that we also have 27, 63, 90.

Triangles with the same angles are defined as similar, so AA should be the answer

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What is the area of a sector with a central angle of 210 degrees and a diameter of 4.6m?
WINSTONCH [101]
Sector area = (central angle / 360) * PI * radius^2
sector area = (210 / 360) * PI * 2.3^2
sector area = (7 / 12) * PI * 5.29
<span><span><span>sector area = 9.6944313302 </span> </span> </span>
<span>sector area = 9.7 square meters (rounded)

Source:
http://www.1728.org/radians.htm

</span>
8 0
3 years ago
Help! Select all of the potential solution(s) of the equation 2log5x = log54.
Nastasia [14]

Answer:

  • x = 2

Step-by-step explanation:

  • 2 log₅ x = log₅ 4
  • 2 log₅ x = log₅ 2²
  • 2 log₅ x = 2 log₅ 2
  • log₅ x = log₅ 2
  • x = 2
7 0
3 years ago
Please I’ll give u brainlesst there is an image attached
-Dominant- [34]

Answer:

I could only find a single semi-complete question on that paper due to the quality of the picture.  <u>The carbon dioxide and water escape from the tube, because as gases, they do not have a definite shape or volume, and instead expand to fit whatever container they are in.</u>

Hope it helps

5 0
3 years ago
1. Use the formula S(d)=√9.8d to calculate the estimated speed, in meters per second, of a tsunami if the disturbance occurred a
postnew [5]

Answer: 1. 210 meters per second .

2.  756  kilometers per hour.

Step-by-step explanation:

Given : The formula S(d)=\sqrt{9.8d} to calculate the estimated speed, in meters per second of a tsunami.

1. If the disturbance occurred at an ocean depth of 4,500 meters.

Then put d= 4500 in the above formula , we get

S(d)=\sqrt{9.8\times4500}

S(d)=\sqrt{44100}=\sqrt{21\times21\times10\times10}\\\\=\sqrt{210^2}=210

Hence, if the disturbance occurred at an ocean depth of 4,500 meters , the estimated speed would be 210 meters per second .

Also, A meter per second is equal to 3.6 kilometers per hour.

i.e. 1 meter per second = 3.6 kilometers per hour

Then by unitary method ,

210 meters per second  =3.6\times210 kilometers per hour

=756  kilometers per hour.

3 0
3 years ago
out of 30 questions on the maths test tomi knew the answer to 27 of them what percentage of questions did tomi know the answer f
Vedmedyk [2.9K]

Answer:

90

Step-by-step explanation:

\frac{27}{30}  \times 100

so after we cut the nessecary we get 90%

Hope this helps you

Mark as the brainlist

thank you

8 0
3 years ago
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