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rjkz [21]
3 years ago
8

Gary invested $1,000 into an account earning interest at an annual rate of 5% compounded annually. Each year, he deposited an ad

ditional $1,000, and made no withdrawals. When he closed the account, he had a balance of $4,525.64. How much interest would Gary earn in that same time if he invests $10,000 and deposits $10,000 into the account each year?
Mathematics
1 answer:
coldgirl [10]3 years ago
6 0
This one is too complicated for me
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What is the number of terms in this geometric series?<br> 1+2+4...+128
Stella [2.4K]
The answer is : a^2=1 x 2^n-1

To check if it’s correct

a^2= 1 x 2^2-1

a^2 = 1x 2
a^2 = 2

Hope this helps!



5 0
2 years ago
A set of headphones takes 5 minutes to charge up to 3 hours play. What is the unit rate?
Burka [1]

Answer:

1.666667 headphones per hour (simplify this)

Step-by-step explanation:

divide the top and bottom by 3 and you should get your answer

4 0
2 years ago
If x^2=20 what is the value of x
tankabanditka [31]

Answer:

Step-by-step explanation:

x^2=20

just square both sides and u get

x = 4.472135955

6 0
3 years ago
Read 2 more answers
a manufacturer has determined that if his company sells x items per day then their profit is given by P=-x^2+ 700 x-10000 euros.
Radda [10]

Answer:

15

Step-by-step explanation:

To find the minimum amount of items, x, that need to be sold for the manufacturer to make a profit, we can use the quadratic formula

x = \frac{-b+\sqrt{b^{2}-4ac } }{2a}; x=  \frac{-b-\sqrt{b^{2}-4ac } }{2a}

x= \frac{-700+\sqrt{700^{2}-4(a)(-10000) } }{2(1)}; x= \frac{-700-\sqrt{700^{2}-4(a)(-10000) } }{2(1)}

x= \frac{-700+\sqrt{530000} }{2}; x= \frac{-700-\sqrt{530000} }{2}

x=\frac{-700+100\sqrt{53} }{2}; x=\frac{-700-100\sqrt{53} }{2};

x=-350 + 50\sqrt53 = 14.005; x = -350 - 50\sqrt53 = -714.005

In context of the problem, we can only rely on the positive value, as the negative value would lead to a loss of profit.

(-714.005)^2+700(-714.005)-10000=-0.360

Furthermore, we must round to the nearest whole number, as you cannot make part of an item.

Lastly, if you were to plug in 14 into the equation for Profit, you would still have a negative number (i.e. a negative profit), thus requiring the manufacturer to make no less than 15 items to make a profit:

(14)^2+700(14)-10000=-4\\\\(15)^2+700(15)-10000=725

3 0
2 years ago
Suppose that $6500 is placed in an account that pays 17% interest compounded each year. Assume that no withdrawals are made from
MatroZZZ [7]

Answer: $7,605

Step-by-step explanation:

At the end of 1 years, the amount in the account will be:

= Principal * (1 + rate)^ no. of periods

= 6,500 * (1 + 17%)

= $7,605

4 0
2 years ago
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