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Katyanochek1 [597]
3 years ago
15

How much higher is 0.25 meters than 0.0254 meters (with real objects)

Physics
1 answer:
sineoko [7]3 years ago
6 0

Answer:

0.2246 meters

Explanation:

.25-0.0254 meters = 0.2246 meters

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When the displacement in SHM is equal to 1/3 of the amplitude xm, what fraction of the total energy is (a) kinetic energy and (b
Nesterboy [21]

Answer:

Explanation:

Given

Displacement is \frac{1}{3} of Amplitude

i.e. x=\frac{A}{3} , where A is maximum amplitude

Potential Energy is given by

U=\frac{1}{2}kx^2

U=\frac{1}{2}k(\frac{A}{3})^2

U=\frac{1}{18}kA^2

Total Energy of SHM is given by

T.E.=\frac{1}{2}kA^2

Total Energy=kinetic Energy+Potential Energy

K.E.=\frac{1}{2}kA^2 -\frac{1}{18}kA^2

K.E.=\frac{8}{18}kA^2

Potential Energy is \frac{1}{8} th of Total Energy

Kinetic Energy is \frac{8}{9} of Total Energy

(c)Kinetic Energy is 0.5\times \frac{1}{2}kA^2

P.E.=\frac{1}{4}kA^2

\frac{1}{2}kx^2=\frac{1}{4}kA^2

x=\frac{A}{\sqrt{2}}                  

7 0
3 years ago
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How does the epidermis protect our skin
Darina [25.2K]
From harmful radiation from our sun!!!!!
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4 years ago
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Which of the following is a valuable part of the scientific method?
yulyashka [42]
Trial and error

scientific laws and theories are proven by experimental data and large bodies of evidence.
7 0
3 years ago
What controls the frequency of a wave?
sashaice [31]

Answer:

Wave frequency can be measured by counting the number of crests (high points) of waves that pass the fixed point in 1 second or some other time period. The higher the number is, the greater the frequency of the waves. ... For example, it is the distance between two adjacent crests in the transverse waves in the diagram.

Explanation:

4 0
3 years ago
How many atoms are in a 2.70 cm × 2.70 cm × 2.70 cm cube of aluminum?
Bess [88]

First, we calculate for the total volume of aluminum. The volume of a cube is:

V = s * s * s = s^3

V = (2.70 cm)^3

V = 19.683 cm^3

Assuming atmospheric temperature, the density of aluminum is about 2.70 g / cm^3. Therefore the equivalent mass of aluminum is:

m = 19.683 cm^3 * 2.70 g / cm^3

m = 53.1441 g

The molar mass of aluminum is 27 g / mol. Therefore the number of moles is:

n = 53.1441 g / (27 g / mol)

n = 1.9683 mol

Given the number of moles, we can calculate for the number of atoms using Avogadro’s number.

atoms = 1.9683 mol * (6.022 * 10^23 atoms / mol)

<span>atoms = 11.85 * 10^23 atoms               (ANSWER)</span>

4 0
3 years ago
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