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stepan [7]
3 years ago
14

What is the volume V of a sample of 4.00 mol of copper? The atomic mass of copper (Cu) is 63.5 g/mol, and the density of copper

is 8.92 x 10^3kg/m^3. Express your answer in cubic centimeters to 3 significant figures.
Physics
2 answers:
rusak2 [61]3 years ago
7 0

Answer : The volume of a sample of 4.00 mol of copper is 28.5cm^3

Explanation :

First we have to calculate the mass of copper.

\text{ Mass of copper}=\text{ Moles of copper}\times \text{ Molar mass of copper}

\text{ Mass of copper}=(4.00moles)\times (63.5g/mole)=254g

Now we have to calculate the volume of copper.

Formula used :

Density=\frac{Mass}{Volume}

Now put all the given values in this formula, we get:

8.92\times 10^3kg/m^3=\frac{254g}{Volume}

Volume=\frac{254g}{8.92\times 10^3kg/m^3}=2.85\times 10^{-2}L=2.85\times 10^{-2}\times 10^3cm^3=28.5cm^3

Conversion used :

1kg/m^3=1g/L\\\\1L=10^3cm^3

Therefore, the volume of a sample of 4.00 mol of copper is 28.5cm^3

tatyana61 [14]3 years ago
7 0

Answer:V=28.4\times 10^{-6} m^3

Explanation:

Given

no of moles=4

Atomic mass of copper=63.5 g/mol

Density of copper=8.92\times 10^3 kg/m^3

no of moles=\frac{mass of copper}{Atomic weight}

4=\frac{mass}{63.5}

mass=254 gm

and mass=density\times volume

254\times 10^{-3}=8.92\times 10^3\times V

V=\frac{254\times 10^{-3}}{8.92\times 10^3}

V=28.4\times 10^{-6} m^3

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The new magnitude of the force of attraction will be 6 times the original force of attraction

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F₂ = 6Gm₁m₂ / r²

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When light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.

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