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3 years ago

What is the formula for a compound formed between Na and N ?

Chemistry

1 answer:

Nastasia [14]3 years ago

5 0

Answer:

Na₃N

Explanation:

The compound made by sodium and nitrogen is called sodium nitride.

The oxidation state of sodium is +1 it loses its one valance electron and get complete octet while nitrogen have five valance electrons it require three more electron to gain stability.

When it react with sodium it needed three electron that's why three sodium atom are react with one nitrogen atom to make the compound overall neutral.

Na⁺ N³⁻

Na₃⁺³N³⁻

Chemical equation:

6Na + N₂ → 2Na₃N

however this compound us unstable and decompose to gives nitrogen and sodium.

Chemical equation:

2Na₃N → 6Na + N₂

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3 years ago

What is the rate constant of a reaction if rate = 1 x 10-2 (mol/L)/s, [A] is 2 M,

boyakko [2]

The rate constant of a reaction : 8.3 x 10⁻⁴

<h3>Further explanation</h3>

Given

rate = 1 x 10⁻² (mol/L)/s, [A] is 2 M, [B] is 3 M, m = 2, and n = 1

Required

the rate constant

Solution

For aA + bB ⇒ C + D

Reaction rate can be formulated:

$\large{\boxed{\boxed{\bold{r~=~k.[A]^a[B]^b}}}$

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8 0

3 years ago

Read 2 more answers

Codeine C18H21NO3 is a weak organic base. A 5.0 x 10^-3 M solution of codeine has a pH of 9.95. Calculate the value of Kb for th

arsen [322]

Answer:

Kb = $4.45\times10^{-7}\ mol/L$

$p^{Kb}=6.35$

Explanation:

For a weak organic base, the formula to find $p^{OH}$ is given by:

$p^{OH}=p^{K_b}+\log c$

where c is the concentration of base.

Here c= $5\times10^{-3}\ M$

$p^{H}=9.95\\p^{OH}=14-p^{H}=14-9.95=4.05$

Substituting the above values in the formula,we get:

$p^{k_b}=p^{OH}-\log c\\p^{k_b}=4.05-\log (5\times10^{-3})\\p^{K_b}=6.35\\K_b=$antilog 6.35=4.45\times10^{-7}\ mol/L$

Hence:

Kb = $4.45\times10^{-7}\ mol/L$

$p^{Kb}=6.35$

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3 years ago

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AlexFokin [52]

I guess it is the second one but you missed the state symbols.

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3 years ago

Help pleaseeee!!! show work

faltersainse [42]

So we just need to do some conversions. We can convert gallons (gal)---> liters (L) just using a few conversion factors and some simple stoichiometry.

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4 years ago