Centripetal force of satellite = gravitational force between earth and the satellite
(m•v^2)/r = (G•Me•m)/r^2
v^2 = (G•Me)/r
v^2 = 6.67x10^-11 x 5.598x10^24 / 7.5x10^7
v = 2231 m/s
so answer is B
Answer:
86MJ
Explanation:
THE TOPIC FROM WHICH THE QUESTION IS OBTAINED IS WORK, ENERGY AND POWER
- Power is defined as the time rate of doing work.
- Power =
- If the energy use is in joules and the time is in seconds, then power is a measure of watts.
1watt = 1 joule per second.
- According to the question, we need to find how much energy does one house use during each 24 hour day ( Already given time = 24hours) when the average rate of electric energy consumption in one house is 1.0 kW ( we have been given power = 1kW).
- Power = 1kW = 1 × 10³W
- Time = 24hours = 24 ×3600 = 86400seconds.
- It is important we have our time in seconds so as to be consistent with unit and dimension
Power = 
1 × 10³W =
- Energy used =1 × 10³W × 86400
- Energy used = 86400000J = 86.4 ×
W = 86.4MJ
The question requested the answer in 2 significant figures and the answer is 86MJ
Answer:
The acceleration of the ball as it rises to the top of its arc equals 9.807 meters per square second.
Explanation:
Let suppose that maximum height of the arc is so small in comparison with the radius of the Earth.
Since the ball is launched upwards, then the ball experiments a free-fall motion, that is, an uniform accelerated motion in which the element is accelerated by gravity. Then, the acceleration experimented by the motion remains constant at every instant and position.
Besides, the gravitational acceleration in the Earth and, in consequence, the acceleration of the ball as it rises to the top of its arc equals 9.807 meters per square second.
Answer:
899752.13598 N
Explanation:
p = Pressure on the plate = 
A = Area = 
F = Force on the region
When force is divided by area we get pressure

Force is exerted by the atmosphere on a disk-shaped region is 899752.13598 N
Average speed= total distance/total time =12km/h