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olga_2 [115]
2 years ago
8

What is the orbit period of the Hubble space telescope

Physics
1 answer:
Marina86 [1]2 years ago
7 0

Answer:

95 minutes

Explanation:

The Hubble Space Telescope makes one orbit around Earth every 95 minutes. The electromagnetic spectrum shows that visible light is between infrared radiation and ultraviolet radiation. NASA.gov

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A young woman was found dead on the side of the road. Two witnesses said they saw and red cadillac hit her and drive off earlier
nignag [31]
I think the answer would be A. Density because many headlights could have the same density, but the rest of the analysis techniques would be specific to that crime.
7 0
3 years ago
A 34-kg child runs with a speed of 2.8 m/s tangential to the rim of a stationary merrygo-round. The merry-go-round has a momentu
tekilochka [14]

Answer: 0.43\ rad/s

Explanation:

Given

Mass of child m=34\ kg

speed of child is v=2.8\ m/s

Moment of inertia of merry go round is I=510\ kg.m^2

radius r=2.31\ m

Conserving the angular momentum

\Rightarrow mvr=I\omega \\\Rightarrow 34\times 2.8\times 2.31=510\times \omega\\\\\Rightarrow \omega=\dfrac{219.912}{510}\\\Rightarrow \omega=0.43\ rad/s

7 0
2 years ago
Salt is now added to the water in the bucket, increasing the density of the liquid. what happens to the tension in the string ?
AlexFokin [52]

The question involves a ping-pong ball that is held submerged in a bucket by a string attached to the bottom of the bucket.

The answer is the tension of the string will increase. This is because making the water salty increases its density, and consequently, increases its buoyancy. This is why sea water is more buoyant than fresh water. Therefore the ping pong is pushed more upwards by the water when salt is added than initially. This gives the string more tension.


5 0
3 years ago
A closed system’s internal energy changes by 178 J as a result of being heated with 658 J of energy. The energy used to do work
nika2105 [10]

Answer:

480J

Explanation:

Using the formula:

Delta U = Q - W

Q:Heat (J)

Delta U: Changes in internal Energy (J)

W:Work (J)

We can plug in the give numbers, Q and W.

Delta U = 658J - 178J = 480J

6 0
2 years ago
A cubical block of wood, 10.0 cm on a side, floats at the interface between oil and water with its lower surface 1.50 cm below t
bezimeni [28]

Answer:

the gauge pressure at the upper face of the block is 116 Pa

Explanation:

Given the data in the question;

A cubical block of wood, 10.0 cm on a side.

height h = 1.50 cm = ( 1.50 × ( 1 / 100 ) ) m = 0.0150 m

density ρ = 790 kg/m³

Using expression for the gauged pressure;

p-p₀ = ρgh

where, p₀ is atmospheric pressure, ρ is the density of the substance, g is acceleration due to gravity and h is the depth of the fluid.

we know that, acceleration due to gravity g = 9.8 m/s²

so we substitute

p-p₀ = 790 kg/m³gh × 9.8 m/s² × 0.0150 m

= 116.13 ≈ 116 Pa

Therefore, the gauge pressure at the upper face of the block is 116 Pa

4 0
3 years ago
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