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Pani-rosa [81]
2 years ago
13

The maximum permissible workday dose for occupational exposure to radiation is 18 mrem. A 54-kg laboratory technician absorbs 2.

6 mJ of 0.30-MeV gamma rays in a work day. The relative biological effectiveness (RBE) for gamma rays is 1.00. What is the ratio of the equivalent dosage received by the technician to the maximum permissible equivalent dosage?
a) .37
b) .35
c) .27
d) .29
e) .32
Physics
1 answer:
professor190 [17]2 years ago
6 0
32 bsbsbsnsbzhhzsbnsnsnsnsnsjs
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Rudik [331]

Answer:

6

Explanation:

cause logic

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3 years ago
Is it ok as a headline story
katen-ka-za [31]
Ya it looks great to be in a story
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2 years ago
Read 2 more answers
Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 25.0 °C for the following reacti
Yakvenalex [24]

The equilibrium constant of the reaction at 25⁰c will be 426827.5.

<u />

  • <u>Theory-</u>

<u>Equilibrium constant</u> :The equilibrium constant comes from the chemical equilibrium law. For the chemical equilibrium state, at a fixed constant temperature, the ratio of the product of the reaction's multiplication to the concentration of its reactants' multiplication, and each is raised to the power to the corresponding coefficients of the elements in the reaction.

The chemical equilibrium is given by for a general chemical reaction.

a. A+ b. B ⇌ c. C+ d. D,.

Kc =[C]c [D]d/[A]a [B]b.

<u>Gibb's free energy</u> :The second law of thermodynamics can be arranged in such a way that it gives a new expression when a chemical reaction happens at a constant temperature and constant pressure.

G=H-TS

  • <u>Calculations</u>:-

T=25⁰c

G=51.4 x 10³J

\\\\k=GR+\frac{nRT}{Z} \\

k= equilibrium constant ,G=Gibbs free energy ,n= no. of moles ,R=Gas constant ,T=temperature ,Z=compressibility

Ideal.Situation=\left \{ {{Z=1} \atop {n=1}} \right.

\\\\\\k=GR+RT

k=51.4 x 10³ x 8.3 + 8.3 x 25

k=426827.5

To learn equilibrium constant-

<u>brainly.com/question/19669218</u>

#SPJ4

6 0
10 months ago
a person when asked to speak up,increases her sound level from 30dB to 60dB.The amount of power per unit area increased by? a)30
aivan3 [116]

Answer:

d) 1000 times

Explanation:

As we know that difference of sound level is given as

L_2 - L_1 = 10 Log \frac{I_2}{I_1}

so here we need to find the ratio of two intensity

it is given as

Log\frac{I_2}{I_1} = \frac{(L_2- L_1)}{10}

Log\frac{I_2}{I_1} = \frac{60 - 30}{10}

Log\frac{I_2}{I_1} = 3

now we have

\frac{I_2}{I_1} = 10^3

so it is

d) 1000 times

4 0
2 years ago
An empty 2,500 kg train car is headed northbound at a velocity of 5 m/s. Ahead of the first car, an empty 1,500 kg car is headed
Tema [17]

Let the mass of 2500 kg car be m_1 and it's velocity be v_1 and the mass of 1500 kg car be m_2 and it's velocity be v_2 .

After the bumping the mass be M and it's velocity be V.

     By law of conservation of momentum we have

                   m_1v_1+m_2v_2 = MV

                    2500 * 5 + 1500 * 1=4000 * V

                    V = 14000/4000 = 7/2 = 3.5 m/s

So the velocity of the two-car train = 3.5 m/s

9 0
3 years ago
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