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jolli1 [7]
3 years ago
15

A 2.0-kg object moving at 5.0 m/s encounters a 30-Newton restive force

Physics
1 answer:
sveta [45]3 years ago
6 0

The impulse experienced by the object is 3 N s.

<u>Explanation:</u>

Impulse is also termed as change in the momentum of the object. So, it is directly proportional to the force acting on the object and the time for which the force is acting on that object.

Thus, impulse experienced by an object is the product of force acting on the object for a given time period. So, it is the sudden influence of force on the given volume.

As the force is given as 30 N and the duration or the time is given as 0.1 seconds. Then, the impulse will be product of force with duration.

Impulse = Force × ΔTime = Force × Duration

Impulse = 30 × 0.1 = 3 N s.

Thus, the impulse experienced by the object is 3 N s.

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Answer:

488.6KN

Explanation:

Hello!

the first step to solve this problem we must find the pressure exerted at the bottom of the tank (P) which is the sum of the external air pressure (P1 = 92kPa), the pressure inside the tank (P2 = 100kPa) and the pressure due to the weight of the water (P3), taking into account the above we have the following equation

P=P1+P2+P3

to find the pressure at the bottom of the tank due to the weight of the water we use the following equation

P3=\alpha gh

where

α=density=1  g/cm^3=1000kg/M^3

H=height=14.1m

g=gravity=3.71m/s^2

solving

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P=P1+P2+P3

P=100kPa+92kPa+52.3kPa=244.3kPa

finally to solve the problem we remember that the pressure is the force exerted on the area

P=\frac{F}{A} \\F=PA\\F=(244.3kPa)(2m^2)=488.6KN

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3 years ago
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Ede4ka [16]

Answer:

OT

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During the major game it is also important to prevent accidents or big injuries as the equipments protect each vital part of the body.

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