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faust18 [17]
3 years ago
14

What would the answer be with the units?

Mathematics
1 answer:
mars1129 [50]3 years ago
5 0

Which of the following is NOT true about Imhotep?

He was the most powerful pharaoh in the Middle Kingdom.

He was so special that he was believed to become a god after his death.

He was carved onto much of the royal artwork along with Djoser.

He was a doctor, architect and royal adviser.

Which of the following is NOT true about Imhotep?

He was the most powerful pharaoh in the Middle Kingdom.

He was so special that he was believed to become a god after his death.

He was carved onto much of the royal artwork along with Djoser.

He was a doctor, architect and royal adviser.

Which of the following is NOT true about Imhotep?

He was the most powerful pharaoh in the Middle Kingdom.

He was so special that he was believed to become a god after his death.

He was carved onto much of the royal artwork along with Djoser.

He was a doctor, architect and royal adviser.

Which of the following is NOT true about Imhotep?

He was the most powerful pharaoh in the Middle Kingdom.

He was so special that he was believed to become a god after his death.

He was carved onto much of the royal artwork along with Djoser.

He was a doctor, architect and royal adviser.

Which of the following is NOT true about Imhotep?

He was the most powerful pharaoh in the Middle Kingdom.

He was so special that he was believed to become a god after his death.

He was carved onto much of the royal artwork along with Djoser.

He was a doctor, architect and royal adviser.

Which of the following is NOT true about Imhotep?

He was the most powerful pharaoh in the Middle Kingdom.

He was so special that he was believed to become a god after his death.

He was carved onto much of the royal artwork along with Djoser.

He was a doctor, architect and royal adviser.

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A student council sells 44 bouquets for $176. Which equation represents the
vesna_86 [32]

Answer:

y = 4x

Step-by-step explanation:

Given

x = 44

y = 176

Required

Determine the relationship between x and y

First, we calculate the unit rate, using:

y = kx

Where k is the unit rate.

Substitute 176 for y and 44 for y

176 = k * 44

Divide both sides by 44

\frac{176}{44} = \frac{44*k}{44}

\frac{176}{44} = k

4 = k

k = 4

Substitute 4 for k in y = kx

y = 4x

Hence, the relationship between x and y is: y = 4x

4 0
3 years ago
What is the y-intercept and slope <br> of the line
bezimeni [28]

Answer:

In the equation of a straight line (when the equation is written as "y = mx + b"), the slope is the number "m" that is multiplied on the x, and "b" is the y-intercept (that is, the point where the line crosses the vertical y-axis). This useful form of the line equation is sensibly named the "slope-intercept form".

Step-by-step explanation:

7 0
3 years ago
Evaluating Algebraic Expressions
koban [17]
D + t = total earnings
$3h + t = total earnings
$3h + $22 = total earnings

Fill in h as however many hours she is working.
Example: She worked for 8 hrs and got $22 in tips.
$3(8) + $22 = ?
$24 +$22 = $46
6 0
3 years ago
Please help ASAP!! Super appreciated!!! &lt;3
Vedmedyk [2.9K]
The data is not linear. From (3, 1) to (7, 2), we add 4 to the x-value and add 1 to the y-value. This pattern continues for a little while, however, from (11, 3) to (18, 5), we add only 7 to the x-value even though we added 2 to the y-value. Given this information, we can determine that this is not linear data.
5 0
4 years ago
A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t
11Alexandr11 [23.1K]

Answer:

  • <u>Question 1:</u>      dm/dt=0.2m<u />

<u />

  • <u>Question 2:</u>     m=Ae^{(0.2t)}<u />

<u />

  • <u>Question 3:</u>      m=10e^{(0.2t)}<u />

<u />

  • <u>Question 4:</u>      m=10g<u />

Explanation:

<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>

<u></u>

a) By definition:  m'=dm/dt

b)  Given:  rate=0.2m

c) By substitution:  dm/dt=0.2m

<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>

a) <u>Separate variables</u>

     dm/m=0.2dt

b)<u> Integrate</u>

           \int dm/m=\int 0.2dt

            ln(m)=0.2t+C

c) <u>Antilogarithm</u>

       m=e^{0.2t+C}

       m=e^{0.2t}\cdot e^C

         e^C=A\\\\m=Ae^{(0.2t)}

<u>Question 3. Which particular solution matches the additional information?</u>

<u></u>

Use the measured rate of 4 grams per hour after 3 hours

            t=3hours,dm/dt=4g/h

First, find the mass at t = 3 hours

            dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g

Now substitute in the general solution of the differential equation, to find A:

          m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976

Round A to 1 significant figure:

  • A = 10.

<u>Particular solution:</u>

           

             m=10e^{(0.2t)}

<u>Question 4. What was the mass of the bacteria at time =0?</u>

Substitute t = 0 in the equation of the particular solution:

         m=10e^{0}\\\\m=10g

3 0
3 years ago
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