All categories

3 years ago

Referring to the _______scale is a way to estimate the wind speed.

Physics

2 answers:

Jlenok [28]3 years ago

6 0

Answer:

Beaufort Scale

Explanation:

Sir Francis Beaufort, an Irish hydrographer, devised a scale to measure the wind speed in 1805. He devised this scale when he was serving on HMS Woolwich. Known as Beaufort Wind Force Scale, it measures and relates the speed of wind to conditions observed at land or sea. It was first used and officially adopted in 1830 on HMS Beagle where Robert Fitzroy was the captain.

No standard scale was present before the Beaufort scale. Initially, it had 13 classes (0-12) which related the wind condition quality and its effects on sails of a frigate. It was further extended in 1946 with addition of 5 more classes (13 to 17). Although, nowadays this extended scale is used only in mainland China and Taiwan.

Wind speed (as per 1946 scale):

$v = 0.836 B^{\frac{3}{2}}$ m/s

where,

v = equivalent speed of wind 10m above the surface of the sea

B = Beaufort Scale number

disa [49]3 years ago

5 0

Answer:

Beaufort scale

Explanation:

The Beaufort Wind Scale is titled after an admiral in Royal Navy, Sir Francis Beaufort. Of 1805, he created the scale to measure wind velocity by observing how sails shift in the wind.

Beaufort scale is broadly categories the wind in to 12 parts which he termed as Force 0 to Force 12.

force 0 termed as calm with speed less than 1 m/hr

force 1 termed as light air with speed 1- 3 mph

force 2 termed as slight breeze with speed 4-7 mph

force 3 termed as gentle breeze with speed 8-12 mph

force 4 termed as moderate breeze with speed 13-18 mph

force 5 termed as fresh breeze with speed 19-24 mph

force 6 termed as strong breeze with speed 25-31 mph

force 7 termed as moderate gale with speed 32-38 mph

force 8 termed as fresh gale with speed 39-46 mph

force 9 termed as strong gale with speed 47-54 mph

force 10 termed as whole gale with speed 55-63 mph

force 11 termed as storm gale with speed 64 -74 mph

force 12 termed as hurricane with speed 75 mph

You might be interested in

This time, William Tell is shooting at an apple that hangs on a tree (Fig. 3.32). The apple is a horizontal distance of 20.0 m

mart [117]

Answer:

The initial arrow's velocity is 40,9 m/s at 11.9° from the horizontal

Explanation:

In order to find the inital velocity we need to determine its components and the angle that the arrow is launched at.

For horizontal component, we will have:

ν cos(θ)t = x ⇒ cos(θ) = x/νt

For vertical component we will have:

h= v sin(θ)t ₋ gt²÷ 2 ⇒ sin (θ) = h + gt²÷2/νt

From the two equations we got, after noting that the vertical displacement is 3m, we can calculate

tan(θ) = h +gt²÷2/νt/ x÷νt = h+ gt²÷2/x = 3+ 9.8.0.5²÷2/20 = 0.21125

Now we can calculate θ = tan⁻¹(0.21125) ≈ 11.9°

Now that we know the angle we can subtitute at any of the expressions for the two components of the velocity . Let's do this subsitution at the horizontal component:

ν cos(θ)t= x =ν = x/tcos(θ)= 20/ 0.5cos(11.9) ≈ 40.9 m/s.

4 0

3 years ago

a kid on a playground swing makes 6 complete to-and-from swings each 30 seconds (a) the frequency of the swinging is? (b) the pe

Mariana [72]

The frequency is how many per second:

(6 swings)/(30 sec) = (6/30) swing/sec = 0.2 per sec = 0.2 Hz .

The period is how long each one takes, or seconds per swing.
It's exactly the flip of frequency.
So we could just take the frequency, flip it, and find 1 / 0.2 ,
but let's do it the long way:

(30 sec) / (6 swings) = (30/6) sec/swing = 5 seconds .

4 0

3 years ago

Read 2 more answers

Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl

shepuryov [24]

Answer:

b) TA = TB = TC

Explanation:

When put in contact each other, and isolated, both blocks will exchange heat till they reach to thermal equilibrium.
During this process, the body at a higher temperature, will loss heat, tat it will be gained by the other body.
The equilibrium condition will be reached when the following equation be met:

$\Delta Q = c_{st}* m_{A} * (T_{fin} - T_{0A} ) = c_{st}* m_{B} * (T_{0B} - T_{fin} )$

Replacing by the values of T₀A = 300º C, and T₀B = 400ºC, and simplifying common terms as mA = mB, we can solve for Tfin, as follows:

$(400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\ 2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC$

So, when both blocks reach to equilibrium, they will be at a common final temperature, 350ºC.
When put in contact with block C, at the same temperature, at that instant, the three blocks will have the same common temperature of 350 ºC.
So, option b) is the right one.

8 0

3 years ago

What is the force on a 250 kg elevator that is falling freely at 9.8 m/sec2?

Viefleur [7K]

Answer:

Since it is falling freely, the only force on it is its weight, w.

w = m × g = 250 kg × 9.8 m/s^2 = 2450 Newton/N

6 0

3 years ago

Read 2 more answers

Write a description of this race using these words.

podryga [215]

Answer:

Race refers to physical differences that groups and cultures consider socially significant. For example, people might identify their race as Aboriginal, African American or Black, Asian, European American or White, Native American, Native Hawaiian or Pacific Islander, Māori, or some other race.

Explanation:

hope this helps

8 0

3 years ago