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Natali5045456 [20]
3 years ago
14

Referring to the _______scale is a way to estimate the wind speed.

Physics
2 answers:
Jlenok [28]3 years ago
6 0

Answer:

Beaufort Scale

Explanation:

Sir Francis Beaufort, an Irish hydrographer, devised a scale to measure the wind speed in 1805. He devised this scale when he was serving on <em>HMS Woolwich</em>. Known as <em>Beaufort Wind Force Scale, </em>it measures and relates the speed of wind to conditions observed at land or sea. It was first used and officially adopted in 1830 on HMS Beagle where Robert Fitzroy was the captain.

No standard scale was present before the Beaufort scale. Initially, it had 13 classes (0-12) which related the wind condition quality and its effects on sails of a frigate. It was further extended in 1946 with addition of 5 more classes (13 to 17). Although, nowadays this extended scale is used only in mainland China and Taiwan.

Wind speed (as per 1946 scale):

v = 0.836 B^{\frac{3}{2}} m/s

where,

v = equivalent speed of wind 10m above the surface of the sea

B = Beaufort Scale number

disa [49]3 years ago
5 0

Answer:

Beaufort scale

Explanation:

The Beaufort Wind Scale is titled after an admiral in Royal Navy, Sir Francis Beaufort. Of 1805, he created the scale to measure wind velocity by observing how sails shift in the wind.

Beaufort scale is broadly categories the wind in to 12 parts which he termed as Force 0 to Force 12.

force 0 termed as calm with speed less than 1 m/hr

force 1 termed as light air with speed 1- 3 mph

force 2 termed as slight breeze with speed 4-7 mph

force 3 termed as gentle breeze with speed 8-12 mph

force 4 termed as moderate breeze with speed 13-18 mph

force 5 termed as fresh breeze with speed 19-24 mph

force 6 termed as strong breeze with speed 25-31 mph

force 7 termed as moderate gale with speed 32-38 mph

force 8 termed as fresh gale with speed 39-46 mph

force 9 termed as strong gale with speed 47-54 mph

force 10 termed as whole gale with speed 55-63 mph

force 11 termed as storm gale with speed 64 -74 mph

force 12 termed as hurricane with speed 75 mph

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An electron and a proton are each placed at rest in an electric field of 500 N/C. Calculate the speed (and indicate the directio
Bumek [7]

Answer:

For proton: 2592 m/s In the same direction of electric field.

For electron: 4752000 m/s In the opposite direction of electric field.

Explanation:

E = 500 N/C, t = 54 ns = 54 x 10^-9 s,

Acceleration = Force /mass

Acceleration of proton, ap = q E / mp

ap = (1.6 x 10^-19 x 500) / (1.67 x 10^-27) = 4.8 x 10^10 m/s^2

Acceleration of electron, ae = q E / me

ae = (1.6 x 10^-19 x 500) / (9.1 x 10^-31) = 8.8 x 10^13 m/s^2

For proton:

u = 0, ap = 4.8 x 10^10 m/s^2, t = 54 x 10^-9 s

use first equation of motion

v = u + at

vp = 0 + 4.8 x 10^10 x 54 x 10^-9 = 2592 m/s In the same direction of electric field.

For electron:

u = 0, ae = 8.8 x 10^13 m/s^2, t = 54 x 10^-9 s

use first equation of motion

v = u + at

vp = 0 + 8.8 x 10^13 x 54 x 10^-9 = 4752000 m/s In the opposite direction of electric field.

6 0
3 years ago
A satellite’s velocity is 30000m/s. After 60 secs, it’s velocity shows to 15000m/a. What is the satellite’s acceleration?
Orlov [11]

Answer:

Acceleration = 9 × 10^5 m/s^2 ( deceleration )

Explanation:

From the first equation of motion:

V = u + at

15000 = 30000 + 60a

a = ( 15000-30000)/60

a = 9 × 10^5 m/s^2

4 0
3 years ago
4. Uncle Harry weighs 180 pounds. What is his mass in kilograms?
MatroZZZ [7]
180 pounds (lb) converts to 81.647 kilograms (kg).
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2 years ago
Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving -1.72 m/s. What is the veloc
Nuetrik [128]

The velocity of B after elastic collision is 3.45m/s

This type of collision is an elastic collision and we can use a formula to solve this problem.

<h3>Elastic Collision</h3>

v_2 = \frac{2m_1u_1}{m_1+m_2} - \frac{m_1 - m_2}{m_1 + m_2}u_2

The data given are;

  • m1 = 281kg
  • u1 = 2.82m/s
  • m2 = 209kg
  • u2 = -1.72m/s
  • v1 = ?

Let's substitute the values into the equation.

v_1 = \frac{2*281*2.82}{281+209} -\frac{281-209}{281+209}(-1.72)\\v_1 = 3.45m/s

From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.

Learn more about elastic collision here;

brainly.com/question/7694106

4 0
2 years ago
A cat lies on the floor. can you say that no force acts on the cat? or is it correct to say that no net force acts on the cat? e
DIA [1.3K]

Odd though it seems at first, gravity is pulling the cat down while the floor is pushing the cat up - in equal amounts. Forces are absolutely acting on the cat but they balance - so there is no net force.  


5 0
3 years ago
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