The steel plate is 0.3 m thick and has a density of 7850 kg>m3 . determine the location of its center of mass. also find the
reactions at the pin and roller support.
1 answer:
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Answer:
t=15.68 s
Explanation:
Given that
m = 1520 kg
P =75 KW
We know that
Power ,P = F .v
F=force
v=velocity
v= 100 km/h
v=27.77 m/s
75 x 1000 = F x 27.77
F= 2700.75 N
F= m a
m=mass
a=acceleration
2700.75 = 1520 x a
a=1.77 m/s²
time t given as
v= u + a t
27.77 = 0 + 1.77 x t
t=15.68 s
Answer:
distance r from the uranium atom is 18.27 nm
Explanation:
given data
uranium and iron atom distance R = 44.10 nm
uranium atom = singly ionized
iron atom = doubly ionized
to find out
distance r from the uranium atom
solution
we consider here that uranium electron at distance = r
and electron between uranium and iron so here
so we can say electron and iron distance = ( 44.10 - r ) nm
and we know single ionized uranium charge q2= 1.602 × C
and charge on iron will be q3 = 2 × 1.602 × C
so charge on electron is q1 = - 1.602 × C
and we know F =
so now by equilibrium
Fu = Fi
=
put here k = and find r
=
r = 18.27 nm
distance r from the uranium atom is 18.27 nm