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Irina-Kira [14]
3 years ago
5

How many sulfur atoms would be present in 41.8 moles of sulfur?

Chemistry
1 answer:
Montano1993 [528]3 years ago
6 0

Answer:

2.51 x 10*25 atoms

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Mr. Swerdlow wrote a chemical equation on the board and asked his class what should be changed to make it correct. He wrote:
Misha Larkins [42]

Answer is: 3. Water and carbon dioxide should both be moved to the products side, and glucose and oxygen should be moved to the reactants side.

Balanced chemical reaction for cellular respiration (convert biochemical energy):

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy, or:

glucose + oxygen → carbon dioxide + water + energy.

This reaction is exothermic (energy is released).

6 0
3 years ago
Read 2 more answers
Suppose 17. g of hydrochloric cid is mixed with 6.99 g of sodium hydroxide calculate the minimum mass of hydochloric acid taht c
Eva8 [605]

Answer: 10.62g

Explanation:

First let us generate a balanced equation for the reaction.

HCl + NaOH —> NaCl + H2O

Molar Mass of HCl= 1 + 35.5 = 36.5g/mol

Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

From the question,

Mass of HCl = 17g

Mass of NaOH = 6.99g

Converting these Masses to mole, we obtain:

n = Mass / Molar Mass

n of HCl = 17/36.5 = 0.4658mol

n of NaOH = 6.99/40 = 0.1748mol

From the question,

1 mole of NaOH requires 1mole of HCl.

Therefore, 0.1748mol of NaOH will also require 0.1748mol of HCl.

But we were told that 17g( i.e 0.4658mol) of HCl were mixed.

Therefore, the unreacted amount of HCl = 0.4658 — 0.1748 = 0.291mol

Converting this to mass, we have:

Mass of HCl = n x molar Mass

Mass of HCl = 0.291 x 36.5

Mass of HCl = 10.62g

Therefore the left over Mass of HCl is 10.62g

8 0
3 years ago
What is the concentration of h+ ions in a solution of hydrochloric acid that was prepared by diluting 35.0 ml of concentrated (1
Alekssandra [29.7K]
Hydrochloric acid ionisation is as follows;
HCl ---> H⁺ + Cl⁻
HCl is a strong base so there's complete dissociation of acid to H⁺ ions
The number of HCl moles is equivalent to number of H⁺ ions present
1 L of solution contains - 11.6 moles of H⁺ ions
In 35 ml number of moles - 11.6 mol/L / 1000 ml x 35 ml = 0.406 mol
This number of moles are dissolved in 500 ml 
therefore molarity = 0.406 mol /500 ml x 1000 ml = 0.812 M
4 0
3 years ago
Is buoyancy a physical or chemical property?
gizmo_the_mogwai [7]
Buoyancy is considered a physical property. It is a type of physical property because it is related to the density and weight of the item, which are both physical.
7 0
3 years ago
Which are the hybrid orbitals of the carbon atoms in the following molecules? (a) H3C―CH3 sp sp2 sp3 (b) H3C―CH═CH2 sp sp2 sp3 (
kherson [118]

Answer:

(a)  sp³    sp³

   H₃<u>C</u> - <u>C</u>H₃

(b)     sp³           sp²

     H₃<u>C</u> - <u>C</u>H = <u>C</u>H₂

                sp²

(c)     sp³        sp    

    H₃<u>C</u> - <u>C</u> ≡ <u>C</u> - <u>C</u>H₂OH

              sp         sp³

(d)     sp³    sp²    

       H₃<u>C</u> - <u>C</u>H=O

Explanation:

Alkanes or the carbons with all the single bonds are sp³ hybridized.

Alkenes or the carbons with double bond(s) are sp² hybridized.

Alkynes or the carbons with triple bond are sp hybridized.

Considering:

(a) H₃C-CH₃ , Both the carbons are bonded by single bond so both the carbons are sp³ hybridized.

Hence,

 sp³    sp³

H₃<u>C</u> - <u>C</u>H₃

(b) H₃C-CH=CH₂ , The carbon of the methyl group is sp³ hybridized as it is boned via single bonds. The rest 2 carbons are sp² hybridized because they are bonded by double bond.

Hence,

   sp³           sp²

H₃<u>C</u> - <u>C</u>H = <u>C</u>H₂

         sp²

(c) H₃C-C≡C-CH₂OH , The carbons of the methyl group and alcoholic group are sp³ hybridized as it is boned via single bonds. The rest 2 carbons are sp hybridized because they are bonded by triple bond.

Hence,

   sp³        sp    

H₃<u>C</u> - <u>C</u> ≡ <u>C</u> - <u>C</u>H₂OH

         sp         sp³

(d)CH₃CH=O, The carbon of the methyl group is sp³ hybridized as it is boned via single bonds. The other carbon is sp² hybridized because it is  bonded by double bond to oxygen.

Hence,

   sp³    sp²    

 H₃<u>C</u> - <u>C</u>H=O

     

8 0
3 years ago
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