Explanation:
Different atoms binds their outermost shell electrons with different amount of energy.
The amount of energy required to remove an electron from an atom is the ionization energy.
- Ionization energy measures the readiness of an atom to lose electrons.
- From the given problem, we can infer that in group O the ionization energy decreases down the group.
- Helium has the highest ionization energy.
- Down a group on the periodic table, ionization energy decrease because:
- atomic radii increases down the group.
- there is an increasing shielding/screening effect of inner shell electrons on the outermost shell electrons.
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Answer:
as the products of that reaction
Explanation:
Answer:
Average atomic mass of carbon = 12.01 amu.
Explanation:
Given data:
Abundance of C¹² = 98.89%
Abundance of C¹³ = 1.11%
Atomic mass of C¹² = 12.000 amu
Atomic mass of C¹³ = 13.003 amu
Average atomic mass = ?
Solution:
Average atomic mass of carbon = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass of carbon = (12.000×98.89)+(13.003×1.11) /100
Average atomic mass of carbon= 1186.68 + 14.43333 / 100
Average atomic mass of carbon = 1201.11333 / 100
Average atomic mass of carbon = 12.01 amu.