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Irina-Kira [14]
3 years ago
5

How many sulfur atoms would be present in 41.8 moles of sulfur?

Chemistry
1 answer:
Montano1993 [528]3 years ago
6 0

Answer:

2.51 x 10*25 atoms

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The first IE of neon (atomic number 10) is significantly higher than that of argon (atomic number 18) but significantly
lbvjy [14]

Explanation:

Different atoms binds their outermost shell electrons with different amount of energy.

The amount of energy required to remove an electron from an atom is the ionization energy.

  • Ionization energy measures the readiness of an atom to lose electrons.
  • From the given problem, we can infer that in group O the ionization energy decreases down the group.
  • Helium has the highest ionization energy.
  • Down a group on the periodic table, ionization energy decrease because:
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  2. there is an increasing shielding/screening effect of inner shell electrons on the outermost shell electrons.

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Ionization energy brainly.com/question/2153804

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8 0
3 years ago
How many moles are there in 9.115 grams of HCI?​
Crazy boy [7]

I do not know, i just need points :/

8 0
3 years ago
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A compound or material formed by a chemical reaction is known as the of that reaction.
Daniel [21]

Answer:

as the products of that reaction

Explanation:

8 0
3 years ago
Calculate the atomic mass of Carbon if the two common isotopes of carbon have masses of
Mars2501 [29]

Answer:

Average atomic mass of carbon = 12.01 amu.

Explanation:

Given data:

Abundance of C¹² = 98.89%

Abundance of C¹³ = 1.11%

Atomic mass of C¹² = 12.000 amu

Atomic mass of C¹³ = 13.003 amu

Average atomic mass = ?

Solution:

Average atomic mass of carbon = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass of carbon = (12.000×98.89)+(13.003×1.11) /100

Average atomic mass of carbon=  1186.68 + 14.43333 / 100

Average atomic mass of carbon = 1201.11333 / 100

Average atomic mass of carbon = 12.01 amu.

5 0
3 years ago
For a particular reaction, ΔH=−111.4 kJ/mol and ΔS=−25.0 J/(mol·K).
PtichkaEL [24]
That’s the answer ^^^^
3 0
3 years ago
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