Answer is: 3. Water and carbon dioxide should both be moved to the products side, and glucose and oxygen should be moved to the reactants side.
Balanced chemical reaction for cellular respiration (convert biochemical energy):
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy, or:
glucose + oxygen → carbon dioxide + water + energy.
This reaction is exothermic (energy is released).
Answer: 10.62g
Explanation:
First let us generate a balanced equation for the reaction.
HCl + NaOH —> NaCl + H2O
Molar Mass of HCl= 1 + 35.5 = 36.5g/mol
Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol
From the question,
Mass of HCl = 17g
Mass of NaOH = 6.99g
Converting these Masses to mole, we obtain:
n = Mass / Molar Mass
n of HCl = 17/36.5 = 0.4658mol
n of NaOH = 6.99/40 = 0.1748mol
From the question,
1 mole of NaOH requires 1mole of HCl.
Therefore, 0.1748mol of NaOH will also require 0.1748mol of HCl.
But we were told that 17g( i.e 0.4658mol) of HCl were mixed.
Therefore, the unreacted amount of HCl = 0.4658 — 0.1748 = 0.291mol
Converting this to mass, we have:
Mass of HCl = n x molar Mass
Mass of HCl = 0.291 x 36.5
Mass of HCl = 10.62g
Therefore the left over Mass of HCl is 10.62g
Hydrochloric acid ionisation is as follows;
HCl ---> H⁺ + Cl⁻
HCl is a strong base so there's complete dissociation of acid to H⁺ ions
The number of HCl moles is equivalent to number of H⁺ ions present
1 L of solution contains - 11.6 moles of H⁺ ions
In 35 ml number of moles - 11.6 mol/L / 1000 ml x 35 ml = 0.406 mol
This number of moles are dissolved in 500 ml
therefore molarity = 0.406 mol /500 ml x 1000 ml = 0.812 M
Buoyancy is considered a physical property. It is a type of physical property because it is related to the density and weight of the item, which are both physical.
Answer:
(a) sp³ sp³
H₃<u>C</u> - <u>C</u>H₃
(b) sp³ sp²
H₃<u>C</u> - <u>C</u>H = <u>C</u>H₂
sp²
(c) sp³ sp
H₃<u>C</u> - <u>C</u> ≡ <u>C</u> - <u>C</u>H₂OH
sp sp³
(d) sp³ sp²
H₃<u>C</u> - <u>C</u>H=O
Explanation:
Alkanes or the carbons with all the single bonds are sp³ hybridized.
Alkenes or the carbons with double bond(s) are sp² hybridized.
Alkynes or the carbons with triple bond are sp hybridized.
Considering:
(a) H₃C-CH₃ , Both the carbons are bonded by single bond so both the carbons are sp³ hybridized.
Hence,
sp³ sp³
H₃<u>C</u> - <u>C</u>H₃
(b) H₃C-CH=CH₂ , The carbon of the methyl group is sp³ hybridized as it is boned via single bonds. The rest 2 carbons are sp² hybridized because they are bonded by double bond.
Hence,
sp³ sp²
H₃<u>C</u> - <u>C</u>H = <u>C</u>H₂
sp²
(c) H₃C-C≡C-CH₂OH , The carbons of the methyl group and alcoholic group are sp³ hybridized as it is boned via single bonds. The rest 2 carbons are sp hybridized because they are bonded by triple bond.
Hence,
sp³ sp
H₃<u>C</u> - <u>C</u> ≡ <u>C</u> - <u>C</u>H₂OH
sp sp³
(d)CH₃CH=O, The carbon of the methyl group is sp³ hybridized as it is boned via single bonds. The other carbon is sp² hybridized because it is bonded by double bond to oxygen.
Hence,
sp³ sp²
H₃<u>C</u> - <u>C</u>H=O