Answer:
Explanation:
The sealed bottle serves as an open system for the water molecules, thus heat energy can be exchanged with its surroundings. When the bottle is placed in a warm environment, there would be a gradual increase in the thermal energy of the molecules of water due to a change in the temperature of its surroundings.
Thus, the molecules of water closer to the boundary of the bottle absorbs heat, becomes lighter and changes position. This gradual process continues until all molecules attains an average temperature which equals that of the surroundings of the bottle.
Therefore, both the thermal energy and temperature of the water increases.
Answer:
39.240 W
Explanation:
Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is 
At this point we can simply apply the definition of power, that is
, to get the power of the engine is 
Answer:
-15 m/s
Explanation:
The computation of the velocity of the 4.0 kg fragment is shown below:
For this question, we use the correlation of the momentum along with horizontal x axis
Given that
Weight of stationary shell = 6 kg
Other two fragments each = 1.0 kg
Angle = 60
Speed = 60 m/s
Based on the above information, the velocity = v is



= -15 m/s
The magnitude of the magnetic field inside the solenoid is
.
The given parameters;
- <em>length of the solenoid, L = 91 cm = 0.91 m</em>
- <em>radius of the solenoid, r = 1.5 cm = 0.015 m</em>
- <em>number of turns of the solenoid, N = 1300 </em>
- <em>current in the solenoid, I = 3.6 A</em>
The magnitude of the magnetic field inside the solenoid is calculated as;

where;
is the permeability of frees space = 4π x 10⁻⁷ T.m/A

Thus, the magnitude of the magnetic field inside the solenoid is
.
Learn more here:brainly.com/question/17137684