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Free_Kalibri [48]
2 years ago
11

How many moles of MgCl2 are there in 329 g of the compound? Your Answer:

Physics
2 answers:
Nookie1986 [14]2 years ago
6 0

Answer:3.46

Explanation:

mass=329

molar mass=71

no. of moles=329/71

=3.46

Debora [2.8K]2 years ago
5 0

Answer:3.46

Explanation:

mass=329

molar mass=71

no. of moles=329/71

=3.46

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The depth of a pond is 1.5m. Calculate the pressure caused by the water at the bottom of the pond ?​?
zepelin [54]

Answer:

Area=1.5(1.5)=2.25m^2

Force of gravity=10N

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}

⟼Pressure=

Area

Force

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}

⟼Pressure=

2.25

10

\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}

⟼Pressure=4.4Pa

5 0
3 years ago
Nurse wears a uniform in a plural form​
Softa [21]

Answer:

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Explanation:

6 0
3 years ago
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A flat, circular, steel loop of radius 75 cm is at rest in a uniform magnetic field, as shown in an edge-on view in the figure (
SIZIF [17.4K]

The solution to the questions are given as

  • t=40.39 \mathrm{sec}
  • \varepsilon &=(0.12v)e^{0.057t}
  • the direction of induced current will be Counterclock vise.

<h3>What is the direction of the current induced in the loop, as viewed from above the loop.?</h3>

Given, $B(t)=(1.4 T) e^{-0.057 t}$

$\varepsilon m f(\varepsilon)=-\frac{d \phi_{B}}{d t}

\quad$ and, $\phi_{B}=\int B \cdot d A=\int B \cdot d A \cdot \cos \theta$

\begin{aligned}\text { Here, } \theta &=30^{\circ} ; \\A &=\pi r^{2} \\a n \delta, R &=0.75 \mathrm{~m} \\\therefore \varepsilon &=-\frac{d}{d t}(B A \cdot \cos \theta)=-A \cdot \cos \theta \cdot \frac{d}{d t}(B(t)) \\\therefore \varepsilon &=-\pi R^{2} \cdot \cos \theta \cdot \frac{d}{d t}\left(e^{-0.057 t}\right)(1.4 T) \\\therefore \varepsilon &=+\pi(0.75)^{2} \cdot \cos 30 \cdot(0.057)(1.4) \cdot e^{-0.057 t}\left\{\because \frac{d}{d t} e^{-x}=-x \cdot e^{-x} .\right.\end{aligned}

\varepsilon &=(0.12v)e^{0.057t}

(b) Here, $\varepsilon_{0}=0.12 \mathrm{~V} \quad\left(a t_{2} t=0 \mathrm{sec}\right)$

\begin{aligned}&\therefore 1 . \varepsilon_{0}=\varepsilon_{0} \cdot e^{-e .057 t} \\&\therefore e^{0.057 t}=10 \quad \text { (taking log both thesides) } \\&\therefore 0.057 t=\ln (10)=2.303 \\&\therefore t=40.39 \mathrm{sec}\end{aligned}

c)

In conclusion, the direction of the induced current will be Counterclockwise.

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4 0
2 years ago
Tara prepared a report to show how the amplitude of waves affects the energy of waves. Is her graphical representation correct?
Gelneren [198K]

Answer:

It is not correct because the amplitude of the waves can be bigger than others and the graph can be going up and down

Explanation: I got the question right

6 0
3 years ago
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If 12V battery maintains a 4.5A current through a resistor what is the resistance of the resistor?
Dimas [21]

Answer:

2.7ohms

Explanation:

Given parameters:

Voltage of the battery  = 12V

Current  = 4.5A

Unknown:

Resistance of the resistor  = ?

Solution:

From Ohm's law, we know that;

          V  = IR

V is the voltage

I is the current

R is the resistance

  So;

        R  = \frac{V}{I}   = \frac{12}{4.5}    = 2.7ohms

5 0
3 years ago
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