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WINSTONCH [101]

3 years ago

5

forces F1 (east) and F2 are simultaneously applied to a 3.0kg mass. when F2 is east, a=5.0m/s² east and when F2 is west a=1.0m/s

² east. Determine the magnitude of F1 and F2.

1 answer:

zhenek [66]3 years ago

5 0

Answer:

345453-5676

its the right answer

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Arrange the phases of the Moon in order of increasing rising time, from the phase with the earliest rising time at 12:00 a.m. to

ZanzabumX [31]

Answer:

Lets assume the Sun rise time to be 06:00 AM. The rise time of different phases of Moon will be as follows:

12:00 AM : Waning Half

01:00 AM - 05:00 AM : Waning Crescent

06:00 AM : New Moon

07:00 AM - 11:00 AM : Waxing Crescent

12:00 PM : Waxing Half

01:00 PM - 06:00 PM : Waxing Gibbous

06:00 PM : Full Moon

07:00 PM - 09:00 PM : Waning Gibbous

Explanation:

The Moon is the only celestial object which shows visible changes in its shape and rise and set time over a very short period of time i.e. just one day. One can observe it by observing the Moon daily. One will notice the change easily. This happens because of the geometry of the Sun, Earth and Moon. The Moon doesn't have its own light and shines because of the light of Sun.

At any given time half of the Moon would be illuminated by the Sun but how much of this illuminated portion is facing the Earth decides the phase of the Moon visible from the Earth. Due to this the Moon shows us various phases namely: New, Waxing Crescent, Waxing Half, Waxing Gibbous, Full, Waning Gibbous, Waning Half, Waning Crescent.

Also, the Moon revolves around the Earth completing the orbit in 29.5 Days. Everyday the Moon will change its position in the orbit. Due to this the rising time of Moon shifts by approximately 52 minutes daily. So, the New Moon rises with the Sun and Full Moon rises just after the sunset.

Lets assume the Sun rise time to be 06:00 AM. The rise time of different phases of Moon will be as follows:

12:00 AM : Waning Half

01:00 AM - 05:00 AM : Waning Crescent

06:00 AM : New Moon

07:00 AM - 11:00 AM : Waxing Crescent

12:00 PM : Waxing Half

01:00 PM - 06:00 PM : Waxing Gibbous

06:00 PM : Full Moon

07:00 PM - 09:00 PM : Waning Gibbous

5 0

3 years ago

Drag each label to the correct location. Sort the sentences based on whether they describe the properties of a heterogeneous or

Lisa [10]

Answer:

ijpferiukjlwbl aojh oljn,

Explanation:

5 0

3 years ago

alculate the kinetic energies of (a) a 2.00×103-kg automobile moving at 100.0 km/h; (b) an 80.0-kg runner sprinting at 10.0 m/s;

zzz [600]

Answer:

(a) 7.72×10⁵ J

(b) 4000 J

(c) 1.82×10⁻¹⁶ J

Explanation:

Kinetic Energy: This can be defined energy of a body due to its motion. The expression for kinetic energy is given as,

Ek = 1/2mv²................... Equation 1

Where Ek = Kinetic energy, m = mass, v = velocity

(a)

For a moving automobile,

Ek = 1/2mv².

Given: m = 2.0×10³ kg, v = 100 km/h = 100(1000/3600) m/s = 27.78 m/s

Substitute into equation 1

Ek = 1/2(2.0×10³)(27.78²)

Ek = 7.72×10⁵ J

(b)

For a sprinting runner,

Given: m = 80 kg, v = 10 m/s

Substitute into equation 1 above,

Ek = 1/2(80)(10²)

Ek = 40(100)

Ek = 4000 J

(c)

For a moving electron,

Given: m = 9.10×10⁻³¹ kg, v = 2.0×10⁷ m/s

Substitute into equation 1 above,

Ek = 1/2(9.10×10⁻³¹)(2.0×10⁷)²

Ek = 1.82×10⁻¹⁶ J

8 0

3 years ago

The Burj Khalifa in Dubai is the world's tallest building. The structure is 828 m 828 m (2716.5 ft) and has more than 160 storie

Natasha_Volkova [10]

Answer:

h = height of the hotel room from the ground floor = 237.4m

Explanation:

Change in Potential Energy of tourist = ΔPE = PE2 – PE1 = mgh

PE1 is the potential energy of tourist at the ground floor

PE1 is the potential energy of tourist at the top (hotel room)

Given

PE1 = − 2.01 × 10⁵ J

PE2 = 0J

PE2 – PE1 = mgh

0 – (− 2.01 × 10⁵ J) = mgh

2.01 × 10⁵ J = 86.4×9.8×h

h = 2.01 × 10⁵/(86.4×9.8) = 237.4m

8 0

3 years ago

Objects 1 and 2 attract each other with a electrostatic force of 72.0 units. If the distance separating objects 1 and 2 is chang

qaws [65]

Answer:

288.0 units; that is the electrostatic force of attraction become quadruple of its initial value.

Explanation:

If all other parameters are constant,

Electrostatic Force of attraction ∝ (1/r²)

F = (k/r²) = 72.0

If r₁ = r/2, what happens to F₁

F₁ = (k/r₁²) = k/(r/2)² = (4k/r²) = 4F = 4 × 72 = 288.0 units

5 0

3 years ago

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