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WINSTONCH [101]

2 years ago

5

forces F1 (east) and F2 are simultaneously applied to a 3.0kg mass. when F2 is east, a=5.0m/s² east and when F2 is west a=1.0m/s

² east. Determine the magnitude of F1 and F2.

1 answer:

zhenek [66]2 years ago

5 0

Answer:

345453-5676

its the right answer

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A truck moves 60 kilometers east from point A to point B. At point B, it turns back west and stops 15 kilometers away from point

iogann1982 [59]

Answer:

Distance: 75 km

Displacement: 45 km

Explanation:

- Distance is a scalar quantity that refers to the total space covered by an object. It is calculated as the sum of the distances covered in each motion, regardless of their direction. therefore in this case:

distance = 60 km + 15 km = 75 km

- Displacement is a vector quantity whose magnitude is equal to the difference between the final point and the starting point of the motion, so it also takes into account the direction of each motion. In this case, the truck moves 60 km east, and then 15 km west: if we call '0' the starting point, the final point will be then

$p_B = 60 km - 15 km=45 km$

And so the displacement is

$d=p_B - p_A=45 km - 0 = 45 km$

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NEED IT ASAP PLEASE 3 examples of how we use physics in our everyday life. Please explain throughly.

Flauer [41]

Answer:

Alarm Clock. The buzzing sound of an alarm clock helps you wake up in the morning as per your schedule. The sound is something that you can’t see, but hear or experience.
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3 years ago

Which statement accurately describes the ultraviolet catastrophe

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3 years ago

Using a horizontal force of 60 N, a wagon is pushed horizontally across the floor a distance of 12 meters at a constant speed of

RideAnS [48]

Answer:

a) The work done by the force is 720 joules, b) The power supplied by the force is 138 watts.

Explanation:

a) Since force is uniform and parallel to the direction of motion, the work ( $W$ ), in joules, done by the force ( $F$ ), in newtons, is defined by this formula:

$W = F\cdot s$ (1)

Where $s$ is the travelled distance, in meters.

If we know that $F = 60\,N$ and $s = 12\,m$ , then the work done by the force is:

$W = F\cdot s$

$W = (60\,N)\cdot (12\,m)$

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The work done by the force is 720 joules.

b) And an expression for the power supplied by the force ( $\dot W$ ), in watts, is concieved by differentiating (1) in time:

$\dot W = F\cdot \dot s$

Where $\dot s$ is the speed of the wagon, in meters per second.

If we know that $F = 60\,N$ and $\dot s = 2.3\,\frac{m}{s}$ , then the power supplied by the force is:

$\dot W = F\cdot \dot s$

$\dot W = (60\,N)\cdot \left(2.3\,\frac{m}{s} \right)$

$\dot W = 138\,W$

The power supplied by the force is 138 watts.

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