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WINSTONCH [101]
2 years ago
5

forces F1 (east) and F2 are simultaneously applied to a 3.0kg mass. when F2 is east, a=5.0m/s² east and when F2 is west a=1.0m/s

² east. Determine the magnitude of F1 and F2. ​
Physics
1 answer:
zhenek [66]2 years ago
5 0

Answer:

345453-5676

its the right answer

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Cuando el pistón tiene un volumen de 2x10^-4 m^3, el gas en el pistón está a una presión de 150 kPa. El área del pistón es 0.001
Vlad1618 [11]

Answer:

F = 1.128 10⁸ Pa

Explanation:

Pressure is defined by

         P = F / A

If the gas is ideal for equal force eds on all the walls, so on the piston area we have

        F = P A

We reduce the pressure to the SI system

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we calculate

       F = 150 10³ / 0.00133

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A comet is traveling through space with speed 3.01 ✕ 104 m/s when it encounters an asteroid that was at rest. The comet and the
Tcecarenko [31]

Answer: 8.493(10)^{-3} m/s

Explanation:

According to the conservation of linear momentum principle, the initial momentum p_{i} (before the collision) must be equal to the final momentum p_{f} (after the collision):

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In addition, the initial momentum is:

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Where:

m_{1}=1.71(10)^{14} kg is the mass of the comet

m_{2}=6.06(10)^{20} kg is the mass of the asteroid

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And the final momentum is:

p_{f}=(m_{1}+m_{2})V_{f} (3)

Where:

V_{f} is the final velocity

Then :

m_{1}V_{1}+m_{2}V_{2}=(m_{1}+m_{2})V_{f} (4)

Isolating V_{f}:

V_{f}=\frac{m_{1}V_{1}}{m_{1}+m_{2}} (5)

V_{f}=\frac{(1.71(10)^{14} kg)(3.01(10)^{4} m/s)}{1.71(10)^{14} kg+6.06(10)^{20} kg}

Finally:

V_{f}=8.493(10)^{-3} m/s This is the final velocity, which is also in the positive direction.

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Answer:

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