The "meters" measurements refer to the diameter of the objective (the main big-moose lens or mirror).
But light collection depends on the AREA of the objective, and that means the SQUARE of the diameter.
So if you double the 'size' if the telescope, it gathers FOUR TIMES as much light as before.
Fnet=Fapp
manet=Fapp
Solve for m
m=Fapp/anet
m=100N/4m/s^2
so mass must equal 25kg
Assuming this is a frictionless surface
ANSWER
EXPLANATION
A sketch of the vector is shown in the diagram in the attachment.
The side adjacent to the angle we want to find is 3.5 units and the opposite side is 3 units.
Let the angle between the vector and the x-axis be
then,
This implies that,
The correct answer is B
Therefore the angle 40.6° to the nearest tenth.
Absolute pressure at the bottom of the lake = pressure due to water height + Air pressure = Density of water*gravitational acceleration* height + 101.3 kPa
Therefore,
Absolute pressure = 1/1000(1*10^3*9.81*29.1) + 101.3 = 285.471+101.3 = 386.771 kPa
constant voltage of 100 volts and a resistance of 500 ohms.
<span>I = 100 / 500. Current = 0.2 amps </span>
<span> resistance to 200 ohms. I = 100 / 200. Now the current is 0.5 amps.</span>
As we also know that Voltage is directly proportional to the current
Resistance is the proportionality constant.