Answer:
Explanation:
Be M1 and M2 the two massive objects and m the third one
The gravitational force over the third object at the beginning is zero (assuming that the position of the third object is x=0)
when the third object is displaced we have that the new position is x=Δx. Hence
I attached a scheme of the system
I hope this is useful for you
Regards
The force on a charged particle on a magnetic field is given by:
where B is the magnitude of the field, q is the charge of the particle, v is its velocity and θ is the angle between the field and the velocity of the particle.
In this case we have that:
• The magnitude of the field is 0.09 T.
,• The charge of the particle is 3.2 x 10 –19C .
,• The velocity is 3.0 × 10 4 m/s
,• The angle between the field and the velocity is 90°, since they are perpendicular.
Plugging these we have:
Therefore, the force on the charge is: