Answer:
We can conclude by saying that in the beginning current will increase but after sometime, it becomes saturated.
Explanation:
Note: No information on change in number of electron generated.
Since there is a collision, the electrons emitted will not reach the collector at same time. As the voltage is increased, the the speed with which the electrons will reach the collector starts to increase. Due to this, electric current will first increases till all the emitted electrons reach the collector. Since we are not provided with the information that number of electrons generated are changing, after increasing voltage current will increase for some time and then reaches a saturated state.
We can conclude by saying that in the beginning current will increase but after sometime it becomes saturated.
Answer:
Radius between electron and proton
Explanation:
The motion of the electron is carried out in the orbit due to the balancing of the electrostatic force between the proton and the electron and the centripetal force acting on the electron.
The electrostatic force is given as = 
Where,
k = coulomb's law constant (9×10⁹ N-m²/C²)
q₁ and q₂ = charges = 1.6 × 10⁻¹⁹ C
r = radius between the proton and the electron
Also,
Centripetal force on the moving electron is given as:
=
where,
= mass of the electron (9.1 ×10⁻³¹ kg)
V = velocity of the moving electron (given: 6.1 ×10⁵ m/s)
Now equating both the formulas, we have
=
⇒
substituting the values in the above equation we get,
⇒
Answer:
The electric field will be decreased by 29%
Explanation:
The distance between point P from the distance z = 2.0 R
Inner radius = R/2
Outer raidus = R
Thus;
The electrical field due to disk is:
)
Similarly;
However; the relative difference is:
![\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Chat%20%7Bk_a%7D%20-%20%5Chat%20%7Bk_b%7D%7D%7B%5Chat%20%7Bk_a%7D%20%7D%3D%20%5Cdfrac%7BE_a%20-E_a%20%2B%20%5Cdfrac%7B%5Csigma%7D%7B2%20%5Cvarepsilon_o%20%20%5CBig%5B1%20-%20%5Cdfrac%7B2.0%20%5C%20R%7D%7B%5Csqrt%7B%282.0%20%5C%20R%29%5E2%20%2B%20%28%5Cdfrac%7BR%7D%7B2%7D%29%5E2%7D%7D%20%5CBig%5D%20%7D%20%7D%20%7B%20%5Cdfrac%7B%5Csigma%7D%7B2%20%5Cvarepsilon_o%20%5CBig%20%5B%201%20-%20%5Cdfrac%7B2.0%20%5C%20R%7D%7B%5Csqrt%7B%20%282.0%20%5C%20R%29%5E2%20%2B%20%28R%29%5E2%7D%7D%20%5CBig%5D%20%7D%7D)
Answer:
2.4 × 10^(-11) N
Explanation:
F = Gm²/r²
F = 6.67×10^(-11) × 60² / 100²
= 2.4×10^(-11) N
Answer:
Explanation:
Speed of car =22.5miles/hr
U=22.5miles/hour
Applied brake and come to rest
Final velocity, =0
t, =2sec
Given that,
Speed=distance /time
Then,
Distance, =speed, ×time
Converting mile/hour to m/s
Given that
Use: 1 mile= 1600 m, 1 h= 3600s
22.5miles/hour × 1600m/mile × 1hour/3600s
Therefore, 22.5mile/hour=10m/s
Using speed =10m/s
Distance =speed ×time
Distance=10×2
Distance, =20m
The distance travelled before coming to rest is 20m.
