Answer:
The elements in this list are:
Silver, hydrogen, carbon, nitrogen, gold, magnesium, nickel, mercury.
Explanation:
Elements are chemical substances that can be found on the periodic table.
Answer:
7
Explanation:
that is the anwer of the question
Atomic or hybrid orbital on the central br atom makes up the sigma bond between this br and an outer f atom in bromine trifluoride, brf3 is sp2 hybridization
Trigonal hybridization is another name for sp2 hybridization. It entails combining one's' orbital with two 'p' orbitals of equal energy to create a new hybrid orbital known as sp2. A trigonal symmetry combination of s and p orbitals that is kept at 120
One of the hybrid orbitals formed when one s orbital and two p orbitals are mathematically merged to form three new equivalent orbitals orientated toward the corners of a triangle is sp2 hybridization.
The only feasible molecule geometry for sp2 hybridized center atoms is trigonal planar. When all of the bonds are in place, the shape is trigonal planar as well.
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Answer:
37.1°C.
Explanation:
- Firstly, we need to calculate the amount of heat (Q) released through this reaction:
<em>∵ ΔHsoln = Q/n</em>
no. of moles (n) of NaOH = mass/molar mass = (2.5 g)/(40 g/mol) = 0.0625 mol.
<em>The negative sign of ΔHsoln indicates that the reaction is exothermic.</em>
∴ Q = (n)(ΔHsoln) = (0.0625 mol)(44.51 kJ/mol) = 2.78 kJ.
Q = m.c.ΔT,
where, Q is the amount of heat released to water (Q = 2781.87 J).
m is the mass of water (m = 55.0 g, suppose density of water = 1.0 g/mL).
c is the specific heat capacity of water (c = 4.18 J/g.°C).
ΔT is the difference in T (ΔT = final temperature - initial temperature = final temperature - 25°C).
∴ (2781.87 J) = (55.0 g)(4.18 J/g.°C)(final temperature - 25°C)
∴ (final temperature - 25°C) = (2781.87 J)/(55.0 g)(4.18 J/g.°C) = 12.1.
<em>∴ final temperature = 25°C + 12.1 = 37.1°C.</em>
