<span><span><span><span><span>(5)</span><span>(<span>−3</span>)</span></span>−<span><span>(4)</span><span>(<span>−3</span>)</span></span></span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span><span>=<span><span><span><span>−15</span>−<span><span>(4)</span><span>(<span>−3</span>)</span></span></span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span><span><span>−15</span>−<span>(<span>−12</span>)</span></span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span><span>−3</span>−3</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span>−6</span>−<span><span>(3)</span><span>(<span>−3</span>)</span></span></span></span><span>=<span><span>−6</span>−<span>(<span>−9</span>)</span></span></span><span>=<span>3</span></span>
Hey there!!
A chicken has 1 head and 2 feet . A goat has 1 head and 4 feet
For heads, total = 40
Let us take the number of chickens as ' x ' and goats as ' y '
x + y = 40 ------------- ( 1 )
2x + 4y = 150 ----------- ( 2 )
Multiply the first equation with 2
2x + 2y = 80
2x + 4y = 150
Subtract the first equation from the first
2y = 70
y = 35
Number of goats = 35
substitute this in other equation
x + y = 40
x + 35 = 40
x = 5
Number of chickens are 4
Hope it helps!
1=-3x-12
13=-3x
3x=-13
X=-4.33333
Brainliest please? Thanks!
Binomial distribution formula: P(x) = (n k) p^k * (1 - p)^n - k
a) Probability that four parts are defective = 0.01374
P(4 defective) = (25 4) (0.04)^4 * (0.96)^21
P(4 defective) = 0.01374
b) Probability that at least one part is defective = 0.6396
Find the probability that 0 parts are defective and subtract that probability from 1.
P(0 defective) = (25 0) (0.04)^0 * (0.96)^25
P(0 defective) = 0.3604
1 - 0.3604 = 0.6396
c) Probability that 25 parts are defective = approximately 0
P(25 defective) = (25 25) (0.04)^25 * (0.96)^0
P(25 defective) = approximately 0
d) Probability that at most 1 part is defective = 0.7358
Find the probability that 0 and 1 parts are defective and add them together.
P(0 defective) = 0.3604 (from above)
P(1 defective) = (25 1) (0.04)^1 * (0.96)^24
P(1 defective) = 0.3754
P(at most 1 defective) = 0.3604 + 0.3754 = 0.7358
e) Mean = 1 | Standard Deviation = 0.9798
mean = n * p
mean = 25 * 0.04 = 1
stdev = 
stdev = 
= 0.9798
Hope this helps!! :)
