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Rzqust [24]
3 years ago
6

A stock solution containing Mn2 ions was prepared by dissolving 1.269 g pure manganese metal in nitric acid and diluting to a fi

nal volume of 2.000 L. The following solutions were then prepared by dilution: For solution A, 40.00 mL of stock solution was diluted to 1500.0 mL. For solution B, 10.00 mL of solution A was diluted to 250.0 mL. For solution C, 20.00 mL of solution B was diluted to 550.0 mL. a Calculate the concentration of the stock solution.
Chemistry
1 answer:
SOVA2 [1]3 years ago
8 0

Answer:

B.

Explanation:

Hope this helpssss

<33

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What is 5 divided by 2.7​
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What is the pH of .0003 M of NaOH
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We are given that the concentration of NaOH is 0.0003 M and are asked to calculate the pH

We know that NaOH dissociates by the following reaction:

NaOH → Na⁺ + OH⁻

Which means that one mole of NaOH produces one mole of OH⁻ ion, which is what we care about since the pH is affected only by the concentration of H⁺ and OH⁻ ions

Now that we know that one mole of NaOH produces one mole of OH⁻, 0.0003M NaOH will produce 0.0003M OH⁻

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8 0
3 years ago
How many moles are in 15.0 grams of calcium (Ca)?
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1 mol ---- 40g
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3 years ago
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