If element x has 10 electrons, how many of them will be in the second energy level?

A pendulum consists of a stone with mass m swinging on a string of length L and negligible mass. The stone has a speed of v0 whe

Dmitriy789 [7]

Answer:

(a) $v = \sqrt{ mv_0^2 - 2gL(1-\cos(\theta))}$

(b) $\theta = \arccos(\frac{2gL-v_0^2}{2gL})$

(c) $E_{total} = \frac{1}{2}mv_0^2$

Explanation:

(a) The total mechanical energy of the system is conserved.

$K_A + U_A = K_B + U_B\\\frac{1}{2}mv_0^2 + 0 = \frac{1}{2}mv^2 + mgh \\h = L - L\cos(\theta) = L(1 - \cos\theta)\\\frac{1}{2}mv^2 = \frac{1}{2}mv_0^2 - mgL(1-\cos(\theta))\\v^2 = mv_0^2 - 2gL(1-\cos(\theta))\\v = \sqrt{ mv_0^2 - 2gL(1-\cos(\theta))}$

(b) The conservation of energy states

$K_A + U_A = K_M + U_M\\\frac{1}{2}mv_0^2 + 0 = 0 + mgL(1-\cos(\theta))\\1-\cos(\theta) = \frac{v_0^2}{2gL}\\\cos(\theta) = 1-\frac{v_0^2}{2gL} = \frac{2gL-v_0^2}{2gL}\\\theta = \arccos(\frac{2gL-v_0^2}{2gL})$

(c) As explained in part (a) the total mechanical energy of the system is equal to the initial kinetic energy, since the potential energy of the system at that point is zero.

$E_{total}= K_A + U_A = K_A + 0\\E_{total} = \frac{1}{2}mv_0^2$

8 0

4 years ago

What are the answers to this

elena-s [515]

Answer:

i cant even see that no one can i will answer it if u can make it bigger

Explanation: eyes

8 0

3 years ago

Two very long parallel wires are a distance d apart and carry equal currents in opposite directions. The locations where the net

sergeinik [125]

Answer:

Its not zero anywhere

Explanation:

The magnetic field B at a distance r due to a long conductor carrying current I is given as

B= μol/2pi r

so the net magnetic field due to the current is not zero anywhere

6 0

3 years ago

A sinewave has a period (duration of one cycle) of 645 μs (microseconds). What is the corresponding frequency of this sinewave,

Oliga [24]

The corresponding frequency of this sinewave, in kHz, expressed to 3 significant figures is: 155 kHz.

Given the following data:

Period = 645 μs

Note: μs represents microseconds.

Conversion:

1 μs = $1$ × $10^-6$ seconds

645 μs = $645$ × $10^-6$ seconds

To find corresponding frequency of this sinewave, in kHz;

Mathematically, the frequency of a waveform is calculated by using the formula;

$Frequency = \frac{1}{Period}$

Substituting the value into the formula, we have;

$Frequency = \frac{1}{645 * 10^-6}$

Frequency = 1550.39 Hz

Next, we would convert the value of frequency in hertz (Hz) to Kilohertz (kHz);

Conversion:

1 hertz = 0.001 kilohertz

1550.39 hertz = X kilohertz

Cross-multiplying, we have;

X = $0.001$ × $1550.39$

X = 155039 kHz

To 3 significant figures;

Frequency = 155 kHz

Therefore, the corresponding frequency of this sinewave, in kHz is 155.

Find more information: brainly.com/question/23460034

6 0

3 years ago

I'll mark brainliest if you help me. :)

BaLLatris [955]

Answer:

gravitational potantional energy

Explanation:

ill try to link a source!

edit: https://flexbooks.ck12.org/cbook/ck-12-middle-school-physical-science-flexbook-2.0/section/14.3/primary/lesson/potential-energy-ms-ps#:~:text=Potential%20energy%20due%20to%20the,is%20called%20gravitational%20potential%20energy.

3 0

3 years ago

If element x has 10 electrons, how many of them will be in the second energy level?​

If element x has 10 electrons, how many of them will be in the second energy level?