Question

What is the maximum mass, in kilograms, of (NH4)2U2O7 that can be formed from the reaction of 100 kg of water and 100 kg of ammonia with 481 kg of UO2SO4?

Answer 1

Mass of (NH₄)₂U₂O₇ : 410.05 kg

Further explanation

Reaction

2UO₂SO₄ + 6NH₃ + 3H₂O → (NH₄)₂U₂O₇ + 2(NH₄)₂SO₄

MW UO₂SO₄ :  366.091

MW (NH₄)₂U₂O₇ : 624.131

MW H₂O :  18.0153

MW NH₃ : 17.0306

mol of 100 kg water :

$\tt \dfrac{100}{18.0153}=5.55$

mol of 100 kg ammonia :

$\tt \dfrac{100}{17.036}=5.87$

mol of UO₂SO₄ :

$\tt \dfrac{481}{366.091}=1.314$

Limiting reactants : smallest mol ratio(mol : coefficient)

$\tt \dfrac{5.55}{3}\div \dfrac{5.87}{6}\div \dfrac{1.314}{2}=1.85\div 0.98\div 0.657$

UO₂SO₄ ⇒ Limiting reactants

mol (NH₄)₂U₂O₇ : mol UO₂SO₄

$\tt \dfrac{1}{2}\times 1.314=0.657$

mass (NH₄)₂U₂O₇

$\tt 0.657\times 624.131=410.05$