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arsen [322]
3 years ago
6

A 7-n vector at an angle of 45° to the horizontal has a vertical component that is about _______.

Physics
1 answer:
Katarina [22]3 years ago
4 0
Vectors are easy once you break them down the right way.

Here is a shortcut formula i have got for you to use to find the x & y components of any vecor, once you know the magnitude and angle (theta):

to find the x component, use<em>:
[magnitude] * cos(theta)

to find the y component use:
[magnitude]*sin(theta)

so for this question use:
y = 7 * sin(45) = 4.94N

</em>
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A projectile is launched from ground level at an angle of 30 degrees above the horizontal. Neglect air resistance and consider t
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Answer:

just before landing the ground

Explanation:

Let the velocity of projection is u and the angle of projection is 30°.

Let T is the time of flight and R is the horizontal distance traveled. As there is no force acting in horizontal direction, so the horizontal velocity remains constant. Let the particle hits the ground with velocity v.

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initial vertical component of velocity, uy = u Sin 30

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T = \frac{2u Sin\theta }{g}

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Use first equation of motion

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vy = - u Sin 30

The magnitude of final velocity is given by

v = \sqrt{v_{x}^{2}+v_{y}^{2}}

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v = u

Thus, the velocity is same as it just reaches the ground.

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