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LiRa [457]
3 years ago
7

. The speedometer readings of a car are shown below. Find the acceleration of the car and its displacement.

Physics
1 answer:
Alchen [17]3 years ago
7 0

It is given that u=36km/h

V= 72km/h

We have to convert it into m/s ao we will multiply it with 5/18

U=36×5/18=10

V=72×5/18=20

So acceleration =v-u/t

= 20-10/t

The time will be 9:45-9:25=20min

So we will convert it into second

= 20×60

a=20-10/20×60

=10/20×60

1/120

From  newtons 2nd law

V^2-u^2=2as

S=v^2-u^2/2a

=400-100×120/2

=18000m/s

<em></em>

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Phantasy [73]

Greetings!

The correct answer choice is Choice 4.

<em>Why?</em>

In a scientific experiment the only thing being changed is the independent variable. Everything else should stay the same.

In this experiment, the independent variable is the amount of sunlight each plant should receive. <em>Here's a tip</em>- when looking for and independent variable look for whats being changed on purpose.

Hope this helps!

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dezoksy [38]
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klasskru [66]

The final velocity of the train at the end of the given distance is 7.81 m/s.

The given parameters;

  • initial velocity of the train, u = 6.4 m/s
  • acceleration of the train, a = 0.1 m/s²
  • distance traveled, s = 100 m

The final velocity of the train at the end of the given distance is calculated using the following kinematic equation;

v² = u² + 2as

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v² = 60.96

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v = 7.81 m/s

Thus, the final velocity of the train at the end of the given distance is 7.81 m/s.

Learn more here:brainly.com/question/21180604

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Need help asap; put you as brainliest​
Vera_Pavlovna [14]

Answer:

unmmmmmmmm I think the answerA

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