Answer:
HC₂H₃O₂/KC₂H₃O₂
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the basic buffer solution as:
![ pH=pK_b+log\frac{[salt]}{[acid]} ](https://tex.z-dn.net/?f=%0ApH%3DpK_b%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%0A)
For a best pair, the pKa value must be equal to pH.
NH₃/NH₄Cl forms a basic buffer and cannot account for pH = 5
out of the acidic buffer given,
So, HF , Ka = 3.5 × 10⁻⁴ , So pKa = 3.46
HC₂H₃O₂ , Ka = 1.8 × 10⁻⁵ , So pKa = 4.77
<u>The best pair to show pH = 5 is HC₂H₃O₂/KC₂H₃O₂</u>
Answer:
CH4 +O2 => CO2 + 2 H2O
None were in excess
Explanation:
Equation for the reaction is,
CH4 + O2 =>CO2 +2 H2O
No of moles of CH4 = (20 /1000)/24 =0.02 /24 = 0.00083
No of moles of O2 =20 /24000 = 0.0083
CH4 : O2 = 1:1
THEREFORE
None of the gases were in excess.
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With the equation <span>A₂+2B₂→2AB₂ we know that one mole of A₂ is necessary to react with two moles of B₂ and with that, we obtain two moles of the product. ( you can see this by just seeing what numbers are before the letters)
Since it's needed more quantity of B than A, B is the limited reagent.
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Answer:
c.- How much of the reactants are needed and how much product will made.
Explanation:
The moles is the matter unit used in chemistry to simplify some calculations, instead of using grams. Also the moles are very useful because the chemical reaction can be balanced.
When a Chemical reaction is balanced, then it can be easily to calculate how many moles are necessary to add in a process to obtain a quantity of grams of a product.
