The process is not a redox reaction.
The reaction between ammonia and hydrochloric acid (HCl) to produce ammonium chloride () has modified the oxidation number of no atom in the reactants. As a base, ammonia interacts easily with hydrochloric acid to produce ammonium chloride salt. A neutralization reaction between an acid and a base is what the described process is, and it is NOT a redox reaction.
A reaction is referred to as a redox reaction if two or more reactants belonging to a single reaction exchange one or more electrons, i.e., one reactant releases one or more additional electrons while the other obtains one or additional electrons. The reacted substance that releases electrons is oxidized and becomes a reducing substance. A reduced oxidizing agent is the reactant that accepts electrons.
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Shown above are three simple diatomic molecules. On the left is H2, with a single bond between the H atoms. Since two H atoms have the same electronegativity, they share the electrons evenly. Fluorine is much more electronegative than hydrogen, so the majority of electron density resides on the fluorine atom.
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Answer: CuSO4>2-butanol> C4H9OH>C2H6>C3H8
Explanation:
Ionic substances are highly soluble in water. CuSO4 is an ionic salt composed of Cu2+ and SO42- ions. These ions are solvated in water hence the salt easily dissolves in the surrounding water molecules. this accounts for the fact that it is the most soluble of the five substances in water. 2-butanol contains the -OH group which interacts with water by hydrogen bonding. This accounts for the miscibility of alkanols with water in all proportions. however, this solubility in water decreases as the alky backbone increases. hence C4H9OH is less soluble in water that 2-butanol. Alkanes are usually not quite soluble in water but again solubility decreases with increase in the alky backbone hence propane is less soluble in water than ethane.