Answer:
1.4e+8 bismuth atoms
Explanation:
If 10³ mm = 10¹² pm
then 44 mm = X pm
X = (44 × 10¹²) / 10³ = 44 × 10⁹ pm (which is the cookie diameter in picometers)
Now we can calculate the number of bismuth atoms needed to span the diameter of the cookie:
number of bismuth atoms = cookie diameter / bismuth atom diameter
number of bismuth atoms = 44 × 10⁹ / 320 = 0.1375 × 10⁹ atoms = 1.375 × 10⁸ atoms
And now to respect the answer format requested by the problem:
1.375 × 10⁸ = 1.375e+8 ≈ 1.4e+8
Given is the specific heat of water equal to 4.18 Joule per gram per *C.
This means to raise the temperature of 1 g of water by 1 degree Celsius we need 4.18 joule of energy.
Now, look at the question. We are asked that how much amount of energy would be required to raise the temperature of 25 g of water by (54-50) = 4 degree celsius.
To do so we have formula
Q = m C (temperature difference)
Have a look at pic for answer
Rate of Sulfur dioxide : 2730.44 mL/s
<h3>Further explanation </h3>
Graham's law: <em>the rate of effusion of a gas is inversely proportional to the square root of its molar masses or </em>
the effusion rates of two gases = the square root of the inverse of their molar masses:

or

MW of N₂ = 28 g/mol
MW SO₂ = 64 g/mol

Answer:
Convergent, divergent, transform
Explanation:
Convergent- tectonic plates move towards one another
Divergent- they move away from each other, or in other directions
Transform- tectonic plates slide past/against each other
Answer:
(a) Acid
(b) Base
(c) Acid
(d) Base
Explanation:
According to the Arrhenius acid-base theory:
- An acid is a substance that releases H⁺ in aqueous solution.
- A base is a substance that releases OH⁻ in aqueous solution.
(a) H₂SO₄ is an acid according to the following equation:
H₂SO₄(aq) ⇒ 2 H⁺(aq) + SO₄²⁻(aq)
(b) Sr(OH)₂ is a base according to the following equation:
Sr(OH)₂(aq) ⇄ Sr²⁺(aq) + 2 OH⁻(aq)
(c) HBr is an acid according to the following equation:
HBr(aq) ⇒ H⁺(aq) + Br⁻(aq)
(d) NaOH is a base according to the following equation:
NaOH(aq) ⇒ Na⁺(aq) + OH⁻(aq)