Lipids are a major component of cells?

How many grams of NO are required to produce 121.0 g of N2 in the following reaction? Show all your work4NH3(8) + 6NO(g) → 5N2(g

elena-s [515]

Explanation:

First, let's rewrite the equation here:

4 NH3 + 6 NO -> 5 N2 + 6 H2O.

The equation tells us that 6 moles of NO produces 5 moles of N2.

But the question wants us to find the quantity in grams of NO required if we have 121 g of N2.

1. So first, let's transform 121 g of N2 into moles, using its molar mass (28 g/mol) and the following formula: moles = mass/molar mass

2. Then, we use the equation ratio between NO and N2: 6:5.

3. Then we transform the result into grams of NO, using its molar mass (30.01 g/mol) and the following formula: mass = moles*molar mass

1. moles = 121/28

moles = 4.3 moles of N2

2. 6 moles of NO --- 5 moles of N2

x moles of NO --- 4.3 moles of N2

5x = 4.3*6

x = 25.9/5

x = 5.2 moles of NO

3. mass = 5.2*30.01

mass = 155.6 g

Answer: It will require 155.6 g of NO.

7 0

2 years ago

True or False. A microwave photon has a lower frequency than an infrared (IR) photon.

Murljashka [212]

False ..............................................

6 0

4 years ago

Determine the number of grams of carbon 3.14x 1023 atoms of carbon

tiny-mole [99]

<h3>Answer:</h3>

6.26 g C

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 3.14 × 10²³ atoms C

[Solve] grams C

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of C - 12.01 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 3.14 \cdot 10^{23} \ atoms \ C(\frac{1 \ mol \ C}{6.022 \cdot 10^{23} \ atoms \ C})(\frac{12.01 \ g \ C}{1 \ mol \ C})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 6.26227 \ g \ C$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

6.26227 g C ≈ 6.26 g C

7 0

3 years ago

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If 3.00 g of limestone reacted, what mass of calcium chloride would be produced?

Levart [38]

CaCO₃ → CaCl₂
Ca = 40, C = 12, O = 16, Cl = 35.5
100 →111
3 → x
x = 3.33g

8 0

3 years ago

How many moles of aluminum oxide are in a sample with a mass of 204

rjkz [21]

Answer:

(204 g)/(101.96 g/mol) = 2.001 mol. 2(2.001) = 4.002 moles of aluminium in the sample

Explanation:

6 0

3 years ago

Read 2 more answers