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3 years ago

What happens to the frequency of a wave If the wavelength is decreased by half

Physics

1 answer:

podryga [215]3 years ago

8 0

Answer:

Frequency doubles.

Explanation:

Frequency doubles because Wavelength and Frequency are inversely proportional. That means if one decreases the other one increases. So, if wavelength is half, frequency is the opposite, doubles.

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When Kevin pulls his cotton shirt off his body, the electrons get transferred from the (shirt or body) to the (shirt or body) .

Masja [62]

<span>When Kevin pulls his cotton shirt off his body, the electrons get transferred from the shirt (in form of static charges i.e. electrons to the body. So, the shirt becomes positively charged and Kevin’s body becomes negatively charged.

As a result of charge transfer from the shirt to the body, we can hear a crackling sound. or if observed in dark, a sparkle can be seen.</span>

6 0

3 years ago

A spring of spring constant k=8.25N/m is displaced from equilibrium by a distance of 0.150m. What is the stored energy in the fo

inysia [295]

Answer:

0.0928J

Explanation:

the pulling force of spring F=-kx

where x is the displacement from equilibrium position.

energy stored:

$\int\limits^x_0 {-F} \, dx \\=\int\limits^x_0 {kx} \, dx \\\\=\frac{kx^{2} }{2}$

*** Its fine if you know nothing about calculus. Just apply the equation

$U=\frac{kx^{2} }{2}$

where U is the potential energy of the spring***

put x=0.150, $U=\frac{8.25}{2}$ × $0.150^{2}$ = 0.0928J (corr. to 3 sig. fig.)

4 0

3 years ago

2. State Newton's third law of motion.<br>

Grace [21]

Answer:

Action and reaction are equal but act in opposite directions

4 0

3 years ago

Read 2 more answers

Your car is initially at rest when your hit that gas and the car begins to accelerate at a rate of 1.464 m/s/s. The acceleration

tamaranim1 [39]

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Explanation:

6 0

3 years ago

at certain times the demand for electric energy is low and electric energy is used to pump water to a reservoir 45 m above the g

Readme [11.4K]

The mass of water that must be raised is $5.25\cdot 10^7 kg$

Explanation:

Since the process is 70% efficiency, the power in output to the turbine can be written as

$P_{out} = 0.70 P_{in}$

where $P_{in}$ is the power in input.

The power in input can be written as

$P_{in} = \frac{W}{t}$

where

W is the work done in lifting the water

t = 3 h = 10,800 s is the time elapsed

The work done in lifting the water is given by

$W=mgh$

where

m is the mass of water

$g=9.8 m/s^2$ is the acceleration of gravity

h = 45 m is the height at which the water is lifted

Combining the three equations together, we get:

$P_{out} = 0.70 \frac{mgh}{t}$

Where

$P_{out} = 150 MW = 150\cdot 10^6 W$

And solving for m, we find:

$m=\frac{Pt}{0.70gh}=\frac{(1.50\cdot 10^6)(10800)}{(0.70)(9.8)(45)}=5.25\cdot 10^7 kg$

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3 0

4 years ago