Answer:
B) 71.5 [km]
Explanation:
To solve this problem we will decompose each of the directions in the x & y axes.
To solve this problem we will decompose each of the directions in the x & y axes. also for a greater understanding of the angles, you should look at the attached image, which contains the orientations for each angle (clockwise or counterclockwise).
<u>59.0 km in a direction 30.0° east of north</u>
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![d_{1x}= 59*sin(30) = 29.5[km]\\d_{1y}= 59*cos(30) = 51.09[km]](https://tex.z-dn.net/?f=d_%7B1x%7D%3D%2059%2Asin%2830%29%20%3D%2029.5%5Bkm%5D%5C%5Cd_%7B1y%7D%3D%2059%2Acos%2830%29%20%3D%2051.09%5Bkm%5D)
<u>58.0 km due south</u>
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![d_{2y} = - 58 [km]\\](https://tex.z-dn.net/?f=d_%7B2y%7D%20%3D%20-%2058%20%5Bkm%5D%5C%5C)
<u>It flies 100 km 30.0° north of west</u>
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Now we sum algebraically the components
![d_{x}=29.5-86.6 = -57.1[km]\\d_{y}=51.09 -58+50=43.09[km]\\\\](https://tex.z-dn.net/?f=d_%7Bx%7D%3D29.5-86.6%20%3D%20-57.1%5Bkm%5D%5C%5Cd_%7By%7D%3D51.09%20-58%2B50%3D43.09%5Bkm%5D%5C%5C%5C%5C)
Using the Pythagorean theorem we can find the magnitude of the displacement.
![d = \sqrt{(57.1)^{2} +(43.09)^{2} } \\d= 71.53[km]](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%2857.1%29%5E%7B2%7D%20%2B%2843.09%29%5E%7B2%7D%20%7D%20%5C%5Cd%3D%2071.53%5Bkm%5D)
Heterogeneous because it has less amount of sugar than the regular Pepsi has
Answer:

Explanation:
given,
length of ladder = 10 ft
let x be the distance of the bottom and y be the distance of the top of ladder.
x² + y² = 100
differentiating with respect to time we get
..............(1)
when x = 8 and y = 6 and when \dfrac{dx}{dt} = 1.4ft/s
from equation (1)
now,


let the angle between the ladders be θ

y = xtan θ




Answer:
The change in momentum = -20000 kg m/s.
Explanation:
Mass m = 1000 kg
speed v₁ = 20 m/s
speed v₂ = 0 m/s
We know that,
The change in momentum
ΔP = m (Δv)
ΔP = m (v₂ - v₁)
= 1000 (0 - 20)
= 1000 (-20)
= -20000 kg m/s
Thus, the change in momentum = -20000 kg m/s.
Note: negative sign indicates that the velocity is reducing when it hits the barrier.
Complete Question
The complete question is shown on the uploaded image
Answer:
The tension on the shank is 
Explanation:
From the question we are told that
The strain on the strain on the head is 
The contact area is
Looking at the first diagram
At 600 MPa of stress
The strain is 
At 450 MPa of stress
The strain is 
To find the stress at
we use the interpolation method

Substituting values



Generally the force on each head is mathematically represented as

Substituting values


Now the tension on the bolt shank is as a result of the force on the 6 head which is mathematically evaluated as


