Can someone please tell me how to speed up a chemical reaction??
1 answer:
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Answer:
(a). second order.
(b). zeroth order.
(c). one and a half order.
(d). third order.
Explanation:
Hello,
In this case, you just have to add the concentration's powers in each rate law:
(a)
Just the 2-power is present, so it is a second order law.
(b)
No power is present, so it is a zeroth order law.
(c)
1 plus 1/2 gives 1.5, that is why it is a 1.5 (one and a half) order law.
(d)
2 plus 1 gives 3, that is why it is a third order law.
Best regards.