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skad [1K]
3 years ago
5

What things typically are counted in multiples or fractions of moles

Chemistry
1 answer:
ololo11 [35]3 years ago
7 0

Answer:

Individually well, defined identical chemically units such as molecules, ions, atoms, or electrons

Explanation:

The mole is used as the unit of measurement for substance such as molecules, ions, atoms, or electrons. One mole of a substance is equivalent to 6.02×10²³ particles of the substance. The number, 6.02 × 10²³ is known as Avogadro's number.

The particles quantified as moles are individually well, defined identical chemically units such that the mole can be used to describe a part of a substance or the whole substance consisting of several moles of the substance combined.

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What explains the fact that no machine is 100 percent efficient?
const2013 [10]
Your answer here is C.
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A radioactive material, with half-life of six months, has 100 thousand unstable nuclei.
goldfiish [28.3K]

Answer:

See Explanation

Explanation:

Given that;

N/No = (1/2)^t/t1/2

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3 0
3 years ago
1) Calculate the molar mass of Tryptophan.
mestny [16]

Answer:

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6 0
3 years ago
What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP?
BigorU [14]
Mg reaction with O₂ gas will produce MgO so the equation will be
2Mg+O₂⇒2MgO. (You have to find the equation in order two figure out the number of moles of O₂ that will react with 1 mole of MgO).

The first step is to find the number of moles of Mg in 4.03g of Mg.  You can do this by dividing 4.03g Mg by its molar mass (which is 24.3g/mol) to get 0.1658mol Mg.  Then you have to find the number of moles of O₂ that will react with 0.1658mol Mg.  To do this you need to use the fact that 1mol O₂ will react with 2mol Mg (this reatio is from the chemical equation) so you have to multiply 0.1658mol Mg by (1mol O₂)/(2mol Mg) to get 0.0829mol O₂.  From here you would usually use PV=nRT and solve for V However, the question tells us that we are at STP, that means you can use the fact that 22.4L of gas is 1 mol of gas at STP.  Using that information we can find the volume of O₂ gas by mulitlying 0.0829mol O₂ by 22.4L/mol to get 1.857L which equals 1857mL.
therefore, 1857mL of O₂ gas will react with 4.03g of Mg.

I hope this helps. Let me know in the comments if anything is unclear.
6 0
3 years ago
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