Answer:
The white powder is not sugar, so Christy's hypothesis is incorrect . Christy's next step should be to identify substances that have the measured molecular mass.
Explanation:
First you need to know how many moles you would get from 165 g of carbon dioxide.
Carbon = 12
Oxygen 2 = 16 x 2 = 32
Total: 32 + 12 = 44
- Use proportions
1 mol CO2 x 1 mol CO2 44 g
---------------- = ---------- or ----------------- = ----------
44 g 165 x 165 g
165/44 = 3.75 moles CO2
- Last step is to multiply the amount of moles by Avagadros number, 6.02 x 10^23
3.75 x 6.02 x 10^23 = 2.25 x 10^24 molecules
- Keep in mind if your answer can be a little different than mind if you either round or keep the same numbers. I hope this Really Helps ! c:
Aluminum can be oxidized by 
and 
<h3>What is oxidizing?</h3>
Some of the metal corrodes (or oxidizes) and forms the corresponding metal oxide on the surface as a result of a chemical reaction between the metal surface and the oxygen in the air. The corrosion products that occur in some metals, like steel, are highly apparent and loose.
According to reactivity series (The array of metals in the descending order of their reactivities is referred to as the metals' reactivity series. It is sometimes referred to as the metals in the activity series.)
Lithium and calcium ions are more reactive than aluminum ion and they are less electronegative.
Since silver and tin are more electronegative than aluminum so, they cannot oxidize aluminum.
∴ and 
ions can oxidize aluminum.
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Answer:
That a chemical change has taken place
Explanation:
Because your changing the substances identity
The combination of a hydrogen atom in a molecule and the oxygen atom in another molecule leads to hydrogen bonding. Option D
<h3>How does hydrogen bond occur?</h3>
For hydrogen bond to occur, hydrogen must be bonded to a highly electronegative atoms in a direct covalent linkage. This accounts for the high boiling point of water.
Thus we can say that a hydrogen bond occurred when a hydrogen from one molecule and an oxygen from another molecule. Option D
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