Answer:
electrical conduction through a gas in an applied electric field
Explanation:
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webpage of a scientist who is trying to sell a new invention
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umiversity should be objective impartial
The kinetic energy of the vehicle should be such it balances the centripetal and centrifugal forces whereas coming into and crossing the curve. whereas coming into, the driving force ought to scale back speed by gently persist brakes, till apex purpose has been reached. this can be the nearest purpose of the car to the within of curve line. Once that has been reached, accelerator ought to be gently pressed to use some force to pull the car<span> out of the curve.
Explanation:
He should slowly slow down the speed
</span>The brake is hard<span> as </span>potential in the<span> entry to the curve, then with less force as </span>you start<span> turning. The slowest </span>purpose ought to<span> be at the apex of the curve, </span>once that you're fast once more.
<span>Your tires have a limit to their grip before they slip (skid). </span>the concept<span> is to manage the forces on them. The </span>additional<span> lateral force from the </span>turn there's<span>, the less linear force </span>you'll<span> use braking or </span>fast.
<span>This is why corners </span>are<span> the passing zones on the track. If </span>you'll<span> out-brake </span>the opposite<span> guy going into the </span>flip<span>, </span>you'll<span> be </span>quicker within the turn, however<span> brake too late and </span>you will not<span> be </span>ready to flip while not<span> skidding.</span>
By formula, Kinetic Energy is:
<span>mass of the body time (the </span>speed<span> of the body) </span>everywhere two.
The mass of the body remains constant.
<span>Velocity is variable.</span>
Answer:
v = 6.72 m/s
Explanation:
Given that,
Vertical height, h = 2.31 m
We need to find the speed at the bottom of the slide. Let the speed be v. We can find it using the conservation of energy such that,
Put all the values,
So, her speed at the bottom of the slide is equal to 6.72 m/s.