Sodium atom , potassium atom and cesium atom have the same group number which is group 1
Answer:
We need 69 grams of NaHCO3
Explanation:
Step 1: Data given
Volume = 550 mL = 0.550 L
Molarity H2SO4 = 0.75 M
Step 2: The balanced equation
H2SO4(aq) + 2NaHCO3(aq) → Na2SO4(aq) + 2H2O(l) + 2CO2(g)
Step 3: Calculate moles of H2SO4
Moles H2SO4 = molarity * volume
Moles H2SO4 = 0.75 M * 0.550 L
Moles H2SO4 = 0.4125 moles H2SO4
Step 4: Calculate moles NaHCO3
For 1 mol H2SO4 we need 2 moles NaHCO3 to produce 1 mol Na2SO4 and 2 moles H2O and 2 Moles CO2
For 0.4125 moles H2SO4 we need 2*0.4125 = 0.825 moles NaHCO3
Step 5: Calculate mass NaHCO3
Mass NaHCO3 = moles * molar mass
Mass NaHCO3 = 0.825 moles * 84.0 g/mol
Mass NaHCO3 = 69.3 grams ≈ 69 grams
We need 69 grams of NaHCO3
First, we can see that the output is a salt and water which means that the reactants were an acid and a base. Since the given reactant is a base, thus, NH4OH is excluded as it is also a base.
Now, examining the outputs of the reactions, we will find that they are composed mainly of sodium, hydrogen, oxygen and carbon. This excludes H3PO4 as it contains phosphorus.
The last step is to compare between the number of moles of each element in the output with those in the input. The output has 1 sodium mole, 2 carbon moles, 5 hydrogen moles and 3 oxygen moles.
The given input (NaOH) has 1 sodium, 1 oxygen and 1 hydrogen moles. Therefore, the other input (reactant) should have 2 carbon, 4 hydrogen and 2 oxygen moles.
Based on this, the right solution is CH3COOH.