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ehidna [41]
2 years ago
15

What is true of boric acid? PLEASE HELP

Chemistry
1 answer:
RSB [31]2 years ago
6 0
It’s the third option
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3.Write the chemical equation for the reaction when methane burns in (2)
IceJOKER [234]

Answer:

a)CH4 + O2 = CO2 + H2O

b)4CH4+5O=2CO+8H2O+2C

5 0
3 years ago
Given the heat change per mole for the combustion of methanol (-726 kJ/mol), predict the heat change that would occur if 0.200 m
DochEvi [55]

Answer:

-145.2kJ

Explanation:

Enthalpy is an extensive property as its value depends on the amount of substance present in the system.

If the enthalpy for one mole of methanol = -726 kJ/mol;

The Enthalpy for 0.2 mol is given as;

Enthalpy = 0.200 * 726

Enthalpy = -145.2kJ

It would take -145.2kJ for 0.200 mol of methanol to undego the combustion reaction.

8 0
2 years ago
Giving out 15 free pts bc im in a good mood :)
Artemon [7]

Answer:

thank you my friend

Explanation:

6 0
2 years ago
I need help solving this!
zmey [24]

Answer: Moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

Explanation:

Given: Mass of methane = 146.6 g

As moles is the mass of a substance divided by its molar mass. So, moles of methane (molar mass = 16.04 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{146.6 g}{16.04 g/mol}\\= 9.14 mol

The given reaction equation is as follows.

C + 2H_{2} \rightarrow CH_{4}

This shows that 2 moles of hydrogen gives 1 mole of methane. Hence, moles of hydrogen required to form 9.14 moles of methane is as follows.

Moles of H_{2} = \frac{9.14}{2}\\= 4.57 mol

Thus, we can conclude that moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

5 0
3 years ago
How is a chemical change different from a physical change?
DaniilM [7]
A physical change<span> in a substance doesn't </span>change<span> what the substance is. In a </span>chemical change<span> where there is a </span>chemical reaction<span>, a new substance is formed and energy is either given off or absorbed.</span>
6 0
3 years ago
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